Vlad77 wrote:

Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?

(A) 1/6

(B) 1/8

(C) 1/12

(D) 1/16

(E) 1/24

the easiest way to solve this problem is to plug in a number. 3,2,4 are denominators so let's take 24

first day 24-24/3=16 parts left

second day 16-16/2=8 parts left

third day 8-3*8/4=2 parts left

we get 2 out 24 parts remained unmoved or 2/24 or 1/12

Answer is C.

P.S. Vlad, ty otkuda? Kuda sobiraeshsya postupat'?