Vlad77 wrote:
Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24
the easiest way to solve this problem is to plug in a number. 3,2,4 are denominators so let's take 24
first day 24-24/3=16 parts left
second day 16-16/2=8 parts left
third day 8-3*8/4=2 parts left
we get 2 out 24 parts remained unmoved or 2/24 or 1/12
Answer is C.
P.S. Vlad, ty otkuda? Kuda sobiraeshsya postupat'?