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# Raymond took several days to mow a certain lawn. He mowed

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Senior Manager
Joined: 13 Mar 2007
Posts: 262
Location: Russia, Moscow
Raymond took several days to mow a certain lawn. He mowed  [#permalink]

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Updated on: 25 May 2007, 06:32
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100% (00:06) correct 0% (00:00) wrong based on 11 sessions

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Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24

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Originally posted by Vlad77 on 25 May 2007, 05:01.
Last edited by Vlad77 on 25 May 2007, 06:32, edited 1 time in total.
Senior Manager
Joined: 03 May 2007
Posts: 253
Re: PS question - explanation is needed!!!  [#permalink]

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25 May 2007, 06:21
Raymond took several days to mow a certain lawn. He mowed of the lawn the first day, of the remaining unmowed portion the second day, and of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24

the question is incomplete. I know how to solve it but I need numbers.
Senior Manager
Joined: 13 Mar 2007
Posts: 262
Location: Russia, Moscow
Re: PS question - explanation is needed!!!  [#permalink]

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25 May 2007, 06:33
Sergey_is_cool wrote:
Raymond took several days to mow a certain lawn. He mowed of the lawn the first day, of the remaining unmowed portion the second day, and of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24

the question is incomplete. I know how to solve it but I need numbers.

Sorry, ya popravil
Senior Manager
Joined: 03 May 2007
Posts: 253
Re: PS question - explanation is needed!!!  [#permalink]

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25 May 2007, 06:41
Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24

the easiest way to solve this problem is to plug in a number. 3,2,4 are denominators so let's take 24

first day 24-24/3=16 parts left
second day 16-16/2=8 parts left
third day 8-3*8/4=2 parts left

we get 2 out 24 parts remained unmoved or 2/24 or 1/12

P.S. Vlad, ty otkuda? Kuda sobiraeshsya postupat'?
VP
Joined: 08 Jun 2005
Posts: 1068

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25 May 2007, 06:43
loan size = x

first day - x/3

second day 2/3*1/2*x = 2/6*x = x/3

third day = x/3*3/4 = 3*x/12 = x/4

total = x/4+x/3+x/3 = 11*x/12

1-(11*x/12) = x/12

the answer is (C)

Intern
Joined: 04 Feb 2007
Posts: 35

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25 May 2007, 06:50
1
Unmowed fraction on the third day=1 - (Ist day fraction+ IInd day fraction+ IIIrd day fraction) =1- [1/3+ {remaining=A}*1/2 + {remaining=B}*3/4) =1- (1/3+1/3+1/4)
=1/12 (C)...ANS
WHERE A=(1-1/3)=2/3
B=1- {1/3 + A*1/2}=1/3
Manager
Joined: 22 May 2007
Posts: 110

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25 May 2007, 07:15
The answer is C.

1/3 done on the first day - 2/3 remains
2/3 x 1/2 or 2/6 goes to the "done" section so 4/6 - 2/6 = 2/6 reamins un-done.
Third day - 2/6 or 4/12 is not done yet. We complete 3/4 of 4/12 or 3/12.
So 4/12 - 3/12 remains incomplete. Ans. 1/12
Senior Manager
Joined: 27 Jul 2006
Posts: 273

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26 May 2007, 10:52
tak mnogo Russkikh na forum. Interesna...
Senior Manager
Joined: 03 May 2007
Posts: 253

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26 May 2007, 10:54
popravochka, ne russkih a russkogovoryashih. ya iz Ukraini, Hayabusa iz Bolgarii
Senior Manager
Joined: 13 Mar 2007
Posts: 262
Location: Russia, Moscow
Re: PS question - explanation is needed!!!  [#permalink]

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27 May 2007, 06:28
Sergey_is_cool wrote:
Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24

the easiest way to solve this problem is to plug in a number. 3,2,4 are denominators so let's take 24

first day 24-24/3=16 parts left
second day 16-16/2=8 parts left
third day 8-3*8/4=2 parts left

we get 2 out 24 parts remained unmoved or 2/24 or 1/12

P.S. Vlad, ty otkuda? Kuda sobiraeshsya postupat'?

Thanks for the explanation !!!

P.S. Ya iz Moskvi (tochnee iz Mitisch). Sobiraus postupat v top10 americanskih bs. GMAT zae..., t.e. nadoel ochen silno !!!
Senior Manager
Joined: 13 Mar 2007
Posts: 262
Location: Russia, Moscow

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27 May 2007, 06:30
Thanks for the explanation bratya slavyane!!!
Director
Joined: 30 Nov 2006
Posts: 548
Location: Kuwait

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27 May 2007, 07:55
He mowed 1/3 + ( 1/2 x 2/3 ) + ( 3/4 x 1/2 x 2/3 ) = 1/3 + 1/3 + 3/12
= 2/3 + 3/12 = 8/12 + 3/12 = 11/12
So, what remained unmowed = 1 - 11/12 = 1/12

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Non-Human User
Joined: 09 Sep 2013
Posts: 11655
Re: Raymond took several days to mow a certain lawn. He mowed  [#permalink]

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03 Oct 2018, 09:58
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Re: Raymond took several days to mow a certain lawn. He mowed   [#permalink] 03 Oct 2018, 09:58
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# Raymond took several days to mow a certain lawn. He mowed

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