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Raymond took several days to mow a certain lawn. He mowed

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Raymond took several days to mow a certain lawn. He mowed  [#permalink]

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New post Updated on: 25 May 2007, 06:32
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Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24

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Originally posted by Vlad77 on 25 May 2007, 05:01.
Last edited by Vlad77 on 25 May 2007, 06:32, edited 1 time in total.
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Re: PS question - explanation is needed!!!  [#permalink]

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New post 25 May 2007, 06:21
Vlad77 wrote:
Raymond took several days to mow a certain lawn. He mowed of the lawn the first day, of the remaining unmowed portion the second day, and of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24


the question is incomplete. I know how to solve it but I need numbers.
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Re: PS question - explanation is needed!!!  [#permalink]

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New post 25 May 2007, 06:33
Sergey_is_cool wrote:
Vlad77 wrote:
Raymond took several days to mow a certain lawn. He mowed of the lawn the first day, of the remaining unmowed portion the second day, and of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24


the question is incomplete. I know how to solve it but I need numbers.


Sorry, ya popravil :-D
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Re: PS question - explanation is needed!!!  [#permalink]

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New post 25 May 2007, 06:41
Vlad77 wrote:
Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24


the easiest way to solve this problem is to plug in a number. 3,2,4 are denominators so let's take 24

first day 24-24/3=16 parts left
second day 16-16/2=8 parts left
third day 8-3*8/4=2 parts left

we get 2 out 24 parts remained unmoved or 2/24 or 1/12

Answer is C.

P.S. Vlad, ty otkuda? Kuda sobiraeshsya postupat'?
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New post 25 May 2007, 06:43
loan size = x

first day - x/3

second day 2/3*1/2*x = 2/6*x = x/3

third day = x/3*3/4 = 3*x/12 = x/4

total = x/4+x/3+x/3 = 11*x/12

1-(11*x/12) = x/12

the answer is (C)

:-D
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New post 25 May 2007, 06:50
1
Unmowed fraction on the third day=1 - (Ist day fraction+ IInd day fraction+ IIIrd day fraction) =1- [1/3+ {remaining=A}*1/2 + {remaining=B}*3/4) =1- (1/3+1/3+1/4)
=1/12 (C)...ANS
WHERE A=(1-1/3)=2/3
B=1- {1/3 + A*1/2}=1/3
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New post 25 May 2007, 07:15
The answer is C.

1/3 done on the first day - 2/3 remains
2/3 x 1/2 or 2/6 goes to the "done" section so 4/6 - 2/6 = 2/6 reamins un-done.
Third day - 2/6 or 4/12 is not done yet. We complete 3/4 of 4/12 or 3/12.
So 4/12 - 3/12 remains incomplete. Ans. 1/12
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New post 26 May 2007, 10:52
tak mnogo Russkikh na forum. Interesna...
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New post 26 May 2007, 10:54
popravochka, ne russkih a russkogovoryashih. :) ya iz Ukraini, Hayabusa iz Bolgarii
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Re: PS question - explanation is needed!!!  [#permalink]

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New post 27 May 2007, 06:28
Sergey_is_cool wrote:
Vlad77 wrote:
Raymond took several days to mow a certain lawn. He mowed 1/3 of the lawn the first day, 1/2 of the remaining unmowed portion the second day, and 3/4 of the remaining unmowed portion the third day. What fraction of the lawn remained unmowed at the end of the third day?
(A) 1/6
(B) 1/8
(C) 1/12
(D) 1/16
(E) 1/24


the easiest way to solve this problem is to plug in a number. 3,2,4 are denominators so let's take 24

first day 24-24/3=16 parts left
second day 16-16/2=8 parts left
third day 8-3*8/4=2 parts left

we get 2 out 24 parts remained unmoved or 2/24 or 1/12

Answer is C.

P.S. Vlad, ty otkuda? Kuda sobiraeshsya postupat'?


Thanks for the explanation :lol: !!!

P.S. Ya iz Moskvi (tochnee iz Mitisch). Sobiraus postupat v top10 americanskih bs. GMAT zae..., t.e. nadoel ochen silno :shock: !!!
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New post 27 May 2007, 06:30
Thanks for the explanation :-D bratya slavyane!!!
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New post 27 May 2007, 07:55
He mowed 1/3 + ( 1/2 x 2/3 ) + ( 3/4 x 1/2 x 2/3 ) = 1/3 + 1/3 + 3/12
= 2/3 + 3/12 = 8/12 + 3/12 = 11/12
So, what remained unmowed = 1 - 11/12 = 1/12

Answer: C

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.


If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
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Re: Raymond took several days to mow a certain lawn. He mowed  [#permalink]

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New post 03 Oct 2018, 09:58
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Re: Raymond took several days to mow a certain lawn. He mowed &nbs [#permalink] 03 Oct 2018, 09:58
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