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13 Jan 2007, 02:03
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reflection of a +ve int is obtained by reversing its digits.
(eg. 321 is reflection of 123).
difference b/w a 5 digit int and its reflection must be divisible by
2
4
5
6
9
i took 12345 and 54321 and eliminated 5
then took 22345 and 54322 and eliminated 2, 4 and 6
only ans left was 9.
i believe there must be a better way to solve this problem, since it is an official question and such questions usually test our knowledge of some concept.
thanks in advance!
(eg. 321 is reflection of 123).
difference b/w a 5 digit int and its reflection must be divisible by
2
4
5
6
9
i took 12345 and 54321 and eliminated 5
then took 22345 and 54322 and eliminated 2, 4 and 6
only ans left was 9.
i believe there must be a better way to solve this problem, since it is an official question and such questions usually test our knowledge of some concept.
thanks in advance!
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13 Jan 2007, 04:18
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difference b/w a 5 digit int and its reflection must be divisible by
2
4
5
6
9
let the 5 digit number be ( abcde ) and express it in terms of a place value in the form (100000a+10000b+1000c+100d+10e ) thus
100000a+10000b+1000c+100d+10e - 100000e-10000d - 1000c-100b-10a=
99990a+9900b-9900d-99990e is devisible by 9
edited for more clarity
2
4
5
6
9
let the 5 digit number be ( abcde ) and express it in terms of a place value in the form (100000a+10000b+1000c+100d+10e ) thus
100000a+10000b+1000c+100d+10e - 100000e-10000d - 1000c-100b-10a=
99990a+9900b-9900d-99990e is devisible by 9
edited for more clarity
