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17 Dec 2009, 02:41
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
73% (00:58) correct
27%
(01:06)
wrong
based on 361
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How many integers from 0-50 have a remainder of 3 when divided by 9?
A. 5
B. 6
C. 7
D. 8
E. 9
A. 5
B. 6
C. 7
D. 8
E. 9
17 Dec 2009, 03:13
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zaarathelab
A remainder of 3 when divided by 9 --> \(n=9q+3\), where q is an integer \(\geq{0}\).
\(9q+3<50\) --> \(q<5\frac{2}{9}\), hence q can take 6 values from 0 to \(5\).
Answer: B (6).
Or, one can just manually list the numbers of the form \(n=9q+3\), which are less than 50: 3, 12, 21, 30, 39, and 48. Total of 6 numbers.
General Discussion
17 Dec 2009, 02:55
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All numbers should be of the form 9c+3 where c is a constant.
Min is 3 for c=0
Max in 48 for c=5
The answer should be B = 6
Min is 3 for c=0
Max in 48 for c=5
The answer should be B = 6
