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15 May 2008, 18:16
Kudos
Bookmarks
Thanks alot for your help guys!
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15 May 2008, 19:20
Kudos
Bookmarks
Since we do not have a value for m, (1) is not sufficient.
For (2), the power of 3 is 4n+2.
For any value of n starting from 1,2.. the resulting number will end in a 9.
For n=1, 3\(^\)4n+2 =3\(^\)6=729.
3\(^\)4n+2 + 1 = 729 + 1 = 730.
730/10. Remainder is 0.
Same is the case for n=2,3 and so on. The number will always end in a 9 and tht when added 1, will result in a number directly divisible by 10 leaving a remainder 0.
Hence B.
For (2), the power of 3 is 4n+2.
For any value of n starting from 1,2.. the resulting number will end in a 9.
For n=1, 3\(^\)4n+2 =3\(^\)6=729.
3\(^\)4n+2 + 1 = 729 + 1 = 730.
730/10. Remainder is 0.
Same is the case for n=2,3 and so on. The number will always end in a 9 and tht when added 1, will result in a number directly divisible by 10 leaving a remainder 0.
Hence B.
