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# Scott starts jogging from Point X to Point Y. A half hour later his fr

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Manager
Joined: 23 Nov 2014
Posts: 60
Scott starts jogging from Point X to Point Y. A half hour later his fr  [#permalink]

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18 May 2016, 21:56
2
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Difficulty:

15% (low)

Question Stats:

88% (02:52) correct 12% (03:30) wrong based on 25 sessions

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Scott starts jogging from Point X to Point Y. A half hour later his friend Garrett who jogs 1 mile per hour slower than twoce Scott's rate starts from the same point and follows the same path. If Garrett overtakes Scott in 2 hours, how many miles will garett have covered?

A. 2.5
B. 3.5
C. 4
D. 4.2

Spoiler: :: My solution
I solved this in following approach:
Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x
Distance needs to be equated therefore (2x-1)*2 = x*2.5
X = 4/3; therefore distance of garett is 3.5

What are other approaches to solvin this
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9232
Location: Pune, India
Re: Scott starts jogging from Point X to Point Y. A half hour later his fr  [#permalink]

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18 May 2016, 22:37
3
ruchi857 wrote:
Scott starts jogging from Point X to Point Y. A half hour later his friend Garrett who jogs 1 mile per hour slower than twoce Scott's rate starts from the same point and follows the same path. If Garrett overtakes Scott in 2 hours, how many miles will garett have covered?

A. 2.5
B. 3.5
C. 4
D. 4.2

I solved this in following approach:
Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x
Distance needs to be equated therefore (2x-1)*2 = x*2.5
X = 4/3; therefore distance of garett is 3.5

What are other approaches to solvin this

You can think of it in terms of relative speed too though calculations will be similar.

Scott's speed is S. Garett's speed is 2S - 1. Their relative speed = 2S - 1 - S = S - 1
Relative distance between them is the distance traveled by Scott in half an hour i.e. S/2

Relative Distance = Relative Speed * Time
S/2 = (S - 1)*2
S = 4/3
Distance traveled by Garett is (2*(4/3) - 1)*2 = 3.3 miles

What is the source of this question? Certainly not GMAT specific. There are only 4 options; plus, the question is not accurate. It should mention "approximately".
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Karishma
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Joined: 06 Nov 2014
Posts: 1877
Re: Scott starts jogging from Point X to Point Y. A half hour later his fr  [#permalink]

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19 May 2016, 05:18
ruchi857 wrote:
Scott starts jogging from Point X to Point Y. A half hour later his friend Garrett who jogs 1 mile per hour slower than twoce Scott's rate starts from the same point and follows the same path. If Garrett overtakes Scott in 2 hours, how many miles will garett have covered?

A. 2.5
B. 3.5
C. 4
D. 4.2

I solved this in following approach:
Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x
Distance needs to be equated therefore (2x-1)*2 = x*2.5
X = 4/3; therefore distance of garett is 3.5

What are other approaches to solvin this

You approach is perfectly fine here.
A minor change can be incorporated in the following way:

Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x

Since both are walking in the same direction, relative speed = 2x - 1 - x = x - 1
Relative distance between them = distance covered by Scott in the initial half hour = x/2

x/2 = (x - 1)*2
x = 4x - 4
x = 4/3 miles/hour

Distance covered by Garret in 2 hours = (2(4/3) - 1)*2 = 10/3

Correct Option: B

However, I too agree with Karishma on this not being a GMAT type question.
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Joined: 09 Sep 2013
Posts: 10996
Re: Scott starts jogging from Point X to Point Y. A half hour later his fr  [#permalink]

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08 Aug 2017, 07:23
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Scott starts jogging from Point X to Point Y. A half hour later his fr   [#permalink] 08 Aug 2017, 07:23
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