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Scott starts jogging from Point X to Point Y. A half hour later his fr

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Scott starts jogging from Point X to Point Y. A half hour later his fr [#permalink]

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New post 18 May 2016, 21:56
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84% (02:54) correct 16% (02:06) wrong based on 32 sessions

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Scott starts jogging from Point X to Point Y. A half hour later his friend Garrett who jogs 1 mile per hour slower than twoce Scott's rate starts from the same point and follows the same path. If Garrett overtakes Scott in 2 hours, how many miles will garett have covered?

A. 2.5
B. 3.5
C. 4
D. 4.2


I solved this in following approach:
Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x
Distance needs to be equated therefore (2x-1)*2 = x*2.5
X = 4/3; therefore distance of garett is 3.5

What are other approaches to solvin this
[Reveal] Spoiler: OA

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Re: Scott starts jogging from Point X to Point Y. A half hour later his fr [#permalink]

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New post 18 May 2016, 22:37
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ruchi857 wrote:
Scott starts jogging from Point X to Point Y. A half hour later his friend Garrett who jogs 1 mile per hour slower than twoce Scott's rate starts from the same point and follows the same path. If Garrett overtakes Scott in 2 hours, how many miles will garett have covered?

A. 2.5
B. 3.5
C. 4
D. 4.2


I solved this in following approach:
Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x
Distance needs to be equated therefore (2x-1)*2 = x*2.5
X = 4/3; therefore distance of garett is 3.5

What are other approaches to solvin this


You can think of it in terms of relative speed too though calculations will be similar.

Scott's speed is S. Garett's speed is 2S - 1. Their relative speed = 2S - 1 - S = S - 1
Relative distance between them is the distance traveled by Scott in half an hour i.e. S/2

Relative Distance = Relative Speed * Time
S/2 = (S - 1)*2
S = 4/3
Distance traveled by Garett is (2*(4/3) - 1)*2 = 3.3 miles

What is the source of this question? Certainly not GMAT specific. There are only 4 options; plus, the question is not accurate. It should mention "approximately".
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Re: Scott starts jogging from Point X to Point Y. A half hour later his fr [#permalink]

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New post 19 May 2016, 05:18
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ruchi857 wrote:
Scott starts jogging from Point X to Point Y. A half hour later his friend Garrett who jogs 1 mile per hour slower than twoce Scott's rate starts from the same point and follows the same path. If Garrett overtakes Scott in 2 hours, how many miles will garett have covered?

A. 2.5
B. 3.5
C. 4
D. 4.2


I solved this in following approach:
Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x
Distance needs to be equated therefore (2x-1)*2 = x*2.5
X = 4/3; therefore distance of garett is 3.5

What are other approaches to solvin this


You approach is perfectly fine here.
A minor change can be incorporated in the following way:

Garett's rate (miles/hour) = 2x-1
Scott's rate (miles/hour) = x

Since both are walking in the same direction, relative speed = 2x - 1 - x = x - 1
Relative distance between them = distance covered by Scott in the initial half hour = x/2

x/2 = (x - 1)*2
x = 4x - 4
x = 4/3 miles/hour

Distance covered by Garret in 2 hours = (2(4/3) - 1)*2 = 10/3

Correct Option: B

However, I too agree with Karishma on this not being a GMAT type question.
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Re: Scott starts jogging from Point X to Point Y. A half hour later his fr [#permalink]

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Re: Scott starts jogging from Point X to Point Y. A half hour later his fr   [#permalink] 08 Aug 2017, 07:23
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