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14 Sep 2007, 12:52
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Found this one confusing. Can someone plz explain?
A) I only
B) II only
C) I and III only
D) II and III only
E) I, II and III
Thank you.
A) I only
B) II only
C) I and III only
D) II and III only
E) I, II and III
Thank you.
Archived Topic
Hi there,
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Thank you for understanding, and happy exploring!
14 Sep 2007, 13:29
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My answer is (D)
You have to look at A(i,j) as an unknown variable (i.e x,y,z)
100*A(100) = 99*A(99) ---> given
100*A(100) = 98*A(98) ---> given
99*A(99) = 98*A(98) ---> given
A(100) = 99/100*A(99)
A(99) = 98/99*A(98)
A(98) = 100/98*A(100)
A(98) = 99/98*A(99)
Statement I
2*99/100*A(99) = A(98)+A(99)
198/100*A(99) = 99/98*A(99)+A(99)
198*98*A(99) = 99*A(99)*100+A(99)*98*100
198*98 = 99*100+98*100
198*98 = 100*(99+98)
198*98 = 100*197 ---> false
statements III,II can be true since 1*A(1) = A(1)
the answer is (D)
You have to look at A(i,j) as an unknown variable (i.e x,y,z)
100*A(100) = 99*A(99) ---> given
100*A(100) = 98*A(98) ---> given
99*A(99) = 98*A(98) ---> given
A(100) = 99/100*A(99)
A(99) = 98/99*A(98)
A(98) = 100/98*A(100)
A(98) = 99/98*A(99)
Statement I
2*99/100*A(99) = A(98)+A(99)
198/100*A(99) = 99/98*A(99)+A(99)
198*98*A(99) = 99*A(99)*100+A(99)*98*100
198*98 = 99*100+98*100
198*98 = 100*(99+98)
198*98 = 100*197 ---> false
statements III,II can be true since 1*A(1) = A(1)
the answer is (D)
14 Sep 2007, 14:02
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KillerSquirrel
KillerSquirrel,
Thank you for such a detailed explanation!! I understand that the given formula implies the text in bold is true. I think I would never be able to figure it out on my own.
Thanks!!
