Set A consists of four consecutive integers. Set B consists of all int

Archit3110

I hope you don't mind if I try to answer your question.

So, we have a Set A that consists of four consecutive integers i.e. n, n+1, n+2, n+3.

Set B consists of numbers that result from adding 2 to each integer from Set A (n+2, n+1+2, n+2+2, n+3+2) AND of numbers that result from substracting 2 from each integer from Set A (n-2, n+1-2, n+2-2, n+3-2).

Let's plug in some numbers to make it more clear.

Set A: 1, 2, 3, 4

Set B:
1) numbers that result from ADDING 2 to each integer from Set A: \(1+2\), \(2+2\), \(3+2\), \(4+2\), so 3, 4, 5, 6;
2) numbers that result from SUBSTRACTING 2 from each integer from Set A: \(1-2\), \(2-2\), \(3-2\), \(4-2\), so -1, 0, 1, 2.

Combining: -1, 0, 1, 2, 3, 4, 5, 6 -> Set B contains 8 integers.

So,
Set A no. of integers - Set B no. of integers = \(8 - 4 = 4\)

The difference is 4, answer D.

Hello,

Would anyone mind to help me with this question?

Do we have to count the integers that are in both series too?

i.e.

Set A: 3 4 5 6

Set B + 2: 5 6 7 8
Set B -2: 1 2 3 4

We have the next integers in both Sets A and B: 3 4 5 6

I am confused since if we don't count the doubled integers, then Set A would have 4 integers, just the same as Set B.

Kind regards!

Set A and B are both individual sets and it doesn't matter whether they contain the same numbers. For example, even if Set A consists of 1, 2, 3, 4 and Set B of 1, 2, 3, 4 (the same numbers) it doesn't change the fact, that each set consists of four elements.

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