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Set A consists of four consecutive integers. Set B consists of all int

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Set A consists of four consecutive integers. Set B consists of all int  [#permalink]

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New post 27 Nov 2018, 00:28
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Set A consists of four consecutive integers. Set B consists of all integers that result from adding 2 to each of the integers in set A together with all integers that result from subtracting 2 from each of the integers in set A. How many more integers are in set B than in set A ?

A. 1
B. 2
C. 3
D. 4
E. 8

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Re: Set A consists of four consecutive integers. Set B consists of all int  [#permalink]

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New post 27 Nov 2018, 09:52
D?
Set B will have 8 elements ie, 4 elements more than A
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Re: Set A consists of four consecutive integers. Set B consists of all int  [#permalink]

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New post 27 Nov 2018, 10:19
Bunuel wrote:
Set A consists of four consecutive integers. Set B consists of all integers that result from adding 2 to each of the integers in set A together with all integers that result from subtracting 2 from each of the integers in set A. How many more integers are in set B than in set A ?

A. 1
B. 2
C. 3
D. 4
E. 8


GMATinsight :

Sir could you please help in explaining the last line of the question " with all integers that result from subtracting 2 from each of the integers in set A. How many more integers are in set B than in set A "

I did not understand it..
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Re: Set A consists of four consecutive integers. Set B consists of all int  [#permalink]

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New post 30 Nov 2018, 16:53
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Archit3110

I hope you don't mind if I try to answer your question.

So, we have a Set A that consists of four consecutive integers i.e. n, n+1, n+2, n+3.

Set B consists of numbers that result from adding 2 to each integer from Set A (n+2, n+1+2, n+2+2, n+3+2) AND of numbers that result from substracting 2 from each integer from Set A (n-2, n+1-2, n+2-2, n+3-2).

Let's plug in some numbers to make it more clear.

Set A: 1, 2, 3, 4

Set B:
1) numbers that result from ADDING 2 to each integer from Set A: \(1+2\), \(2+2\), \(3+2\), \(4+2\), so 3, 4, 5, 6;
2) numbers that result from SUBSTRACTING 2 from each integer from Set A: \(1-2\), \(2-2\), \(3-2\), \(4-2\), so -1, 0, 1, 2.

Combining: -1, 0, 1, 2, 3, 4, 5, 6 -> Set B contains 8 integers.

So,
Set A no. of integers - Set B no. of integers = \(8 - 4 = 4\)

The difference is 4, answer D.
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Set A consists of four consecutive integers. Set B consists of all int  [#permalink]

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New post 30 Dec 2018, 22:34
Hello,

Would anyone mind to help me with this question?

Do we have to count the integers that are in both series too?

i.e.

Set A: 3 4 5 6

Set B + 2: 5 6 7 8
Set B -2: 1 2 3 4

We have the next integers in both Sets A and B: 3 4 5 6

I am confused since if we don't count the doubled integers, then Set A would have 4 integers, just the same as Set B.

Kind regards!
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Re: Set A consists of four consecutive integers. Set B consists of all int  [#permalink]

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New post 06 Jan 2019, 09:19
jfranciscocuencag wrote:
Hello,

Would anyone mind to help me with this question?

Do we have to count the integers that are in both series too?

i.e.

Set A: 3 4 5 6

Set B + 2: 5 6 7 8
Set B -2: 1 2 3 4

We have the next integers in both Sets A and B: 3 4 5 6

I am confused since if we don't count the doubled integers, then Set A would have 4 integers, just the same as Set B.

Kind regards!


Set A and B are both individual sets and it doesn't matter whether they contain the same numbers. For example, even if Set A consists of 1, 2, 3, 4 and Set B of 1, 2, 3, 4 (the same numbers) it doesn't change the fact, that each set consists of four elements.
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Re: Set A consists of four consecutive integers. Set B consists of all int   [#permalink] 06 Jan 2019, 09:19
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