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# Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th

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Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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17 Jan 2019, 23:44
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Question Stats:

64% (00:36) correct 36% (01:05) wrong based on 14 sessions

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Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of the integers 1, 4, 6, 8, and 10. If a number in Set A is to be multiplied by a number in Set B, how many different products are possible?

A 5
B 10
C 15
D 20
E 25

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Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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18 Jan 2019, 06:17
Bunuel wrote:
Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of the integers 1, 4, 6, 8, and 10. If a number in Set A is to be multiplied by a number in Set B, how many different products are possible?

A 5
B 10
C 15
D 20
E 25

total no in A = 5 which is multiplied once by 5 different no in B which are also 5
1*5 * 5 = 25
IMO E
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Joined: 15 Jan 2019
Posts: 4
Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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18 Jan 2019, 07:36
Archit3110 wrote:
Bunuel wrote:
Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of the integers 1, 4, 6, 8, and 10. If a number in Set A is to be multiplied by a number in Set B, how many different products are possible?

A 5
B 10
C 15
D 20
E 25

total no in A = 5 which is multiplied once by 5 different no in B which are also 5
1*5 * 5 = 25
IMO E

The question is "How many different products…"
Some products are twice, so the answer can't be [E].

2*6=12 and 3*4=12
2*10=20 and 5*4= 20
3*10=30 and 5*6= 30 etc.
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Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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18 Jan 2019, 07:48
TinscheLA wrote:
Archit3110 wrote:
Bunuel wrote:
Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of the integers 1, 4, 6, 8, and 10. If a number in Set A is to be multiplied by a number in Set B, how many different products are possible?

A 5
B 10
C 15
D 20
E 25

total no in A = 5 which is multiplied once by 5 different no in B which are also 5
1*5 * 5 = 25
IMO E

The question is "How many different products…"
Some products are twice, so the answer can't be [E].

2*6=12 and 3*4=12
2*10=20 and 5*4= 20
3*10=30 and 5*6= 30 etc.

TinscheLA
as per your logic the answer option would be an odd integer value ; since max total values can 25 'odd' and if we remove overlapping pairs 'even' we would end up getting odd-even = odd integer
25 is the max no of product pairs which can be formed
15 would come if we have exactly 5 pairs of overlapping/similar values total overlapping values are coming as '6' i.e " 12,20,30" ;
so the best option here is 25 only...
had 19 been given as answer option ; then it would have been correct...
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Intern
Joined: 15 Jan 2019
Posts: 4
Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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18 Jan 2019, 07:53
Archit3110 wrote:

TinscheLA
as per your logic the answer option would be an odd integer value ; since max total values can 25 'odd' and if we remove overlapping pairs 'even' we would end up getting odd-even = odd integer
25 is the max no of product pairs which can be formed
15 would come if we have exactly 5 pairs of overlapping/similar values total overlapping values are coming as '6' i.e " 12,20,30" ;
so the best option here is 25 only...
had 19 been given as answer option ; then it would have been correct...

I know :D
My answer would have been 22, since you can keep 12,20 and 30.
But since this is not an option, I've got a problem here :D
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Joined: 18 Aug 2017
Posts: 1775
Location: India
Concentration: Sustainability, Marketing
GPA: 4
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Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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18 Jan 2019, 07:57
TinscheLA wrote:
Archit3110 wrote:

TinscheLA
as per your logic the answer option would be an odd integer value ; since max total values can 25 'odd' and if we remove overlapping pairs 'even' we would end up getting odd-even = odd integer
25 is the max no of product pairs which can be formed
15 would come if we have exactly 5 pairs of overlapping/similar values total overlapping values are coming as '6' i.e " 12,20,30" ;
so the best option here is 25 only...
had 19 been given as answer option ; then it would have been correct...

I know :D
My answer would have been 22, since you can keep 12,20 and 30.
But since this is not an option, I've got a problem here :D

TinscheLA
answer cannot be an even integer ;
if 12,20,30 are overlapping in pairs so it would be 6 digits total and answer would be 25-6 = 19

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Intern
Joined: 15 Jan 2019
Posts: 4
Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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18 Jan 2019, 08:20
Archit3110 wrote:
TinscheLA wrote:
Archit3110 wrote:

TinscheLA
as per your logic the answer option would be an odd integer value ; since max total values can 25 'odd' and if we remove overlapping pairs 'even' we would end up getting odd-even = odd integer
25 is the max no of product pairs which can be formed
15 would come if we have exactly 5 pairs of overlapping/similar values total overlapping values are coming as '6' i.e " 12,20,30" ;
so the best option here is 25 only...
had 19 been given as answer option ; then it would have been correct...

I know :D
My answer would have been 22, since you can keep 12,20 and 30.
But since this is not an option, I've got a problem here :D

TinscheLA
answer cannot be an even integer ;
if 12,20,30 are overlapping in pairs so it would be 6 digits total and answer would be 25-6 = 19

I understand what you want to say, but I thought I could keep at least one time 12,20,30 because they are different from the other 19 products. So the answer would be 22.
But since neither 19 nor 22 is an answer choice here, I might just think to complicated and the correct answer is in fact [E)
Manager
Joined: 15 Feb 2018
Posts: 243
Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th  [#permalink]

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18 Jan 2019, 21:24
2 (1, 4, 6, 8, 10) = 2, 8, 12, 16, 20
3 (1, 4, 6, 8, 10) = 3, 12, 18, 24, 30
5 (1, 4, 6, 8, 10) = 5, 20, 30, 40, 50
7 (1, 4, 6, 8, 10) = 7, 28, 42, 56, 70
9 (1, 4, 6, 8, 10) = 9, 36, 54, 72, 90

5+4+3+5+5=22

Re: Set A consists of the integers 2, 3, 5, 7, and 9. Set B consists of th   [#permalink] 18 Jan 2019, 21:24
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