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Set A has 50 members and set B has 53 members. At least 2 of the membe 23 May 2019, 03:51
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45% (medium)

Question Stats:

64% (02:07) correct 36% (02:09) wrong based on 261 sessions

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Set A has 50 members and set B has 53 members. At least 2 of the members in set A are not in set B. Which of the following could be the number of members in set B that are not in set A ?

I. 5
II. 50
III. 53


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III
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E
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Set A has 50 members and set B has 53 members. At least 2 of the membe 23 May 2019, 05:12
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2 ≤ x ≤ 50
Hence, (50-50) ≤ y ≤ (50-2)
or 0 ≤ y ≤ 48

(53-48) ≤ z ≤ (53-0)
5 ≤ z ≤ 53

Bunuel
Set A has 50 members and set B has 53 members. At least 2 of the members in set A are not in set B. Which of the following could be the number of members in set B that are not in set A ?

I. 5
II. 50
III. 53


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III
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Set A has 50 members and set B has 53 members. At least 2 of the membe 23 May 2019, 10:54
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Bunuel
Set A has 50 members and set B has 53 members. At least 2 of the members in set A are not in set B. Which of the following could be the number of members in set B that are not in set A ?

I. 5
II. 50
III. 53


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III
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draw a 2x2 matrix and we see all given values are possible

---sa----nsa----total
sb-48---5-------53
nsb->2-- 0------0
tot--50---5-----
we can have nsb and sa >=2
IMO E
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Set A has 50 members and set B has 53 members. At least 2 of the membe 26 May 2019, 08:24
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Bunuel VeritasKarishma
How come the number of members in set B that are not in set A can be '53'... as already it is mentioned that At least 2 of the members in set A are not in set B . According to me, it should be 5 and 50 and not 53. Please clarify.
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Set A has 50 members and set B has 53 members. At least 2 of the membe 27 May 2019, 19:21
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Bunuel
Set A has 50 members and set B has 53 members. At least 2 of the members in set A are not in set B. Which of the following could be the number of members in set B that are not in set A ?

I. 5
II. 50
III. 53


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III
Show more

If 2 members from set A are not in set B and the other 48 members of set A are also members of set B, then the number of members in set B that are not in set A is 53 - 48 = 5. So Roman numeral I could be true.

If 47 members from set A are not in set B and the other 3 members of set A are also members of set B, then the number of members in set B that are not in set A is 53 - 3 = 50. So Roman numeral II could be true also.

If all 50 members from set A are not in set B, then the number of members in set B that are not in set A is 53. So Roman numeral III could also be true.


Answer; E
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