It is currently 23 Mar 2018, 00:21

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# SET THEORY MAXIMA

Author Message
Manager
Joined: 04 Sep 2006
Posts: 113

### Show Tags

27 Jun 2009, 21:41
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

A company has 30 employees and 3 clubs M, S, and Z. 10 employees joined M, 12 joined S, 5 joined Z. If members of M joined no other clubs, at most how employees joined neither of the clubs?

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Senior Manager
Joined: 23 Jun 2009
Posts: 355
Location: Turkey
Schools: UPenn, UMich, HKS, UCB, Chicago

### Show Tags

28 Jun 2009, 12:51
8 is true. Solution is right.
Manager
Joined: 28 Jan 2004
Posts: 201
Location: India

### Show Tags

29 Jun 2009, 21:13
Refer to the attached Venn diagram
A + B + C + D + E + F + G + X = 30
where X = members no belonging to any club
A = 10
B = C = D = 0 (because of the clause that club M members are not members of any other club)

So equation becomes
E + F + G + X = 20.....................1

Club S has 12 members so
F + G = 12............................2

Club Z has 5 members so
E + F = 5...........................3

We need to find out max. of X. Now X will be max. when E + F + G will be minimum.
Substitute eq. 2 in eq. 1
E + 12 + X = 20
For it to be minimum E can be 0 which leads to Max. X = 8.

This took me less then 1 min. and this is the std. way to solve this.
Why i did not substituted eq. 3 in eq. 1 is a question for you guys

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

Attachments

venn diagram.dot [25 KiB]

Re: SET THEORY MAXIMA   [#permalink] 29 Jun 2009, 21:13
Display posts from previous: Sort by