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27 Jun 2009, 21:41
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A company has 30 employees and 3 clubs M, S, and Z. 10 employees joined M, 12 joined S, 5 joined Z. If members of M joined no other clubs, at most how employees joined neither of the clubs?
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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28 Jun 2009, 12:51
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8 is true. Solution is right.
29 Jun 2009, 21:13
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Refer to the attached Venn diagram
A + B + C + D + E + F + G + X = 30
where X = members no belonging to any club
A = 10
B = C = D = 0 (because of the clause that club M members are not members of any other club)
So equation becomes
E + F + G + X = 20.....................1
Club S has 12 members so
F + G = 12............................2
Club Z has 5 members so
E + F = 5...........................3
We need to find out max. of X. Now X will be max. when E + F + G will be minimum.
Substitute eq. 2 in eq. 1
E + 12 + X = 20
For it to be minimum E can be 0 which leads to Max. X = 8.
This took me less then 1 min. and this is the std. way to solve this.
Why i did not substituted eq. 3 in eq. 1 is a question for you guys
:-D
A + B + C + D + E + F + G + X = 30
where X = members no belonging to any club
A = 10
B = C = D = 0 (because of the clause that club M members are not members of any other club)
So equation becomes
E + F + G + X = 20.....................1
Club S has 12 members so
F + G = 12............................2
Club Z has 5 members so
E + F = 5...........................3
We need to find out max. of X. Now X will be max. when E + F + G will be minimum.
Substitute eq. 2 in eq. 1
E + 12 + X = 20
For it to be minimum E can be 0 which leads to Max. X = 8.
This took me less then 1 min. and this is the std. way to solve this.
Why i did not substituted eq. 3 in eq. 1 is a question for you guys
:-D
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
