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Concentration: International Business, General Management
GPA: 3.86
WE:Accounting (Commercial Banking)
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Sets tough Problem Try it......
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03 Jan 2012, 05:48
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XYZ Tech is an IT company with 100 employees who all are software developers.The ratio of developers working on Java to developers working on PHP is 5:3.The ratio of developers working on PHP to developers working on Java and PHP is 6:4.The ratio of developers working on PHP to developers not working on Java and PHP is 3:1.
Find. 1. How many developers work only on Java? 2. How many developers work only on PHP? 3. How many developers work only on both Java and PHP? 4. How many developers neither work on Java nor PHP?
Answers for the 4 questions are 1.50 2.10 3.20 4.10
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Re: Sets tough Problem Try it......
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03 Jan 2012, 11:13
Still working on figuring out the right answer but the answers posted cannot be correct. They total number of employees in the answers you gave add up to 90 and the total number of employees is 100 will work on the answer and get back to you on that.
Re: Sets tough Problem Try it......
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04 Jan 2012, 01:24
Expert Reply
kotela wrote:
XYZ Tech is an IT company with 100 employees who all are software developers.The ratio of developers working on Java to developers working on PHP is 5:3.The ratio of developers working on PHP to developers working on Java and PHP is 6:4.The ratio of developers working on PHP to developers not working on Java and PHP is 3:1.
Find. 1. How many developers work only on Java? 2. How many developers work only on PHP? 3. How many developers work only on both Java and PHP? 4. How many developers neither work on Java nor PHP?
Answers for the 4 questions are 1.50 2.10 3.20 4.10
There is a problem with the numbers given (as pointed out in the post above). The solution would look something like this:
Ratio of developers working on Java:developers working on PHP = 5:3 Ratio of developers working on PHP:developers working on both = 6:4 = 3:2 Ratio of developers working on PHP:developers not working on Java and PHP = 3:1
Ratio of developers working on Java:developers working on PHP:developers working on both:developers working on neither Java nor PHP = 5:3:2:1
Say, developers working on Java is 5n. Then developers working on PHP is 3n, developers working on both is 2n and developers working on neither is n.
100 - n = 5n + 3n - 2n 100 = 7n n cannot be a non-integral value since it represents the number of people. This is the problem with the numbers here. Either total number of people cannot be 100 or some of the ratios are incorrect. Once we get n, it is straightforward to find everything needed.
Concentration: International Business, General Management
GPA: 3.86
WE:Accounting (Commercial Banking)
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Re: Sets tough Problem Try it......
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04 Jan 2012, 18:11
VeritasPrepKarishma wrote:
kotela wrote:
XYZ Tech is an IT company with 100 employees who all are software developers.The ratio of developers working on Java to developers working on PHP is 5:3.The ratio of developers working on PHP to developers working on Java and PHP is 6:4.The ratio of developers working on PHP to developers not working on Java and PHP is 3:1.
Find. 1. How many developers work only on Java? 2. How many developers work only on PHP? 3. How many developers work only on both Java and PHP? 4. How many developers neither work on Java nor PHP?
Answers for the 4 questions are 1.50 2.10 3.20 4.10
There is a problem with the numbers given (as pointed out in the post above). The solution would look something like this:
Ratio of developers working on Java:developers working on PHP = 5:3 Ratio of developers working on PHP:developers working on both = 6:4 = 3:2 Ratio of developers working on PHP:developers not working on Java and PHP = 3:1
Ratio of developers working on Java:developers working on PHP:developers working on both:developers working on neither Java nor PHP = 5:3:2:1
Say, developers working on Java is 5n. Then developers working on PHP is 3n, developers working on both is 2n and developers working on neither is n.
100 - n = 5n + 3n - 2n 100 = 7n n cannot be a non-integral value since it represents the number of people. This is the problem with the numbers here. Either total number of people cannot be 100 or some of the ratios are incorrect. Once we get n, it is straightforward to find everything needed.
Re: Sets tough Problem Try it......
[#permalink]
04 Jan 2012, 21:24
VeritasPrepKarishma wrote:
kotela wrote:
XYZ Tech is an IT company with 100 employees who all are software developers.The ratio of developers working on Java to developers working on PHP is 5:3.The ratio of developers working on PHP to developers working on Java and PHP is 6:4.The ratio of developers working on PHP to developers not working on Java and PHP is 3:1.
Find. 1. How many developers work only on Java? 2. How many developers work only on PHP? 3. How many developers work only on both Java and PHP? 4. How many developers neither work on Java nor PHP?
Answers for the 4 questions are 1.50 2.10 3.20 4.10
There is a problem with the numbers given (as pointed out in the post above). The solution would look something like this:
Ratio of developers working on Java:developers working on PHP = 5:3 Ratio of developers working on PHP:developers working on both = 6:4 = 3:2 Ratio of developers working on PHP:developers not working on Java and PHP = 3:1
Ratio of developers working on Java:developers working on PHP:developers working on both:developers working on neither Java nor PHP = 5:3:2:1
Say, developers working on Java is 5n. Then developers working on PHP is 3n, developers working on both is 2n and developers working on neither is n.
100 - n = 5n + 3n - 2n 100 = 7n n cannot be a non-integral value since it represents the number of people. This is the problem with the numbers here. Either total number of people cannot be 100 or some of the ratios are incorrect. Once we get n, it is straightforward to find everything needed.
I used the below approach.
let number of only Java = x, number of only PHP = z, number of Java + PHP = y
so acc to the question:
(x+y)/(y+z) = 5/3 (y+z)/y = 6/4 (z+y)/z = 3/1
on solving the above 3 equations we get x=3z, y=2z and z
so x+y+z = 100 => 6z = 100
for the first question we have to get the value of x => 3*50/3 = 50 but for the remaining question I am getting answers in farctions.
I think the question is not correct. Correct me if I am wrong.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.