|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
19 Feb 2017, 08:02
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
85% (01:06) correct
15%
(01:35)
wrong
based on 96
sessions
History
Date
Time
Result
Not Attempted Yet
Seven basketball teams play in a league against each other. At the end of the season, how many different arrangements are there for the top 3 teams in the rankings?
A. 6
B. 42
C. 210
D. 5,040
E. 50,450
A. 6
B. 42
C. 210
D. 5,040
E. 50,450
19 Feb 2017, 08:46
Kudos
Bookmarks
SajjadAhmad
Take the task of arranging the top 3 teams and break it into stages.
Stage 1: Select the 1st place team
There are 7 teams to choose from, so we can complete stage 1 in 7 ways
Stage 2: Select the 2nd place team
Since already selected a team in stage 1, there are now 6 teams remaining to choose from.
So, we can complete stage 2 in 6 ways
Stage 3: Select the 3rd place team
There are now 5 teams remaining to choose from.
So, we can complete stage 3 in 5 ways
By the Fundamental Counting Principle (FCP), we can complete all 3 stages (and thus arrange the top 3 teams) in (7)(6)(5) ways (= 210 ways)
Answer: C
Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. For more information about the FCP, watch this video:
You can also watch a demonstration of the FCP in action here:
19 Feb 2017, 09:59
Kudos
Bookmarks
SajjadAhmad
It's simply 7P3 = 7!/(7-3)! = 210. Selecting 3 out of 7 when the order of the selection matters.
Answer: C.
