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28 Oct 2013, 01:23
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Finding values of X and Y in linear simultaneous equations can be very easy. just follow the method mentioned below.
firstly our formula to find X=numerator/denominator and Y=numerator/denominator.
ideally if we have value for any one variable we need not calculate the value for the other variable , as it can be easily substituted in the equation.
say our 2 equations are
2x+4y=10
3x+2y=11
As per our formula x= Num/deno.
now numerator is obtained by cross multiplying (4*11) and subtracting from it the cross product of (2*10)=44-20=24
and denominator is obtained by cross multiplying (4*3) and subtracting from it the cross product of (2*2)=12-4=8
therefore our value for x = Num/Den = 24/8=3
now we can find the value of Y in similar way. however, it will be time consuming . thus we just substitute the value of X in one of the variable.
2x+4y=10
2(3)+4y=10
y=1
therefore we get our two variables x=3,y=1.
hope this helps for quicker calculations.
For those who are curious how to find value of Y in a similar way the method is mentioned below.
i ll just retype the previous equations for better understanding
2x+4y=10
3x+2y=11
again for Y the same formula=Num/ Den ( but the multiplication is slightly different)
now numerator is obtained by cross multiplying (2*11) and subtracting from it the cross product of (3*10)=22-30=-8
and denominator is obtained by cross multiplying (2*2) and subtracting from it the cross product of (4*3)=4-12=-8
thus Y=num/den=-8/-8=1
y=1.
now we can find the value of X, by substituting the value of Y in any equations, as we did above.
firstly our formula to find X=numerator/denominator and Y=numerator/denominator.
ideally if we have value for any one variable we need not calculate the value for the other variable , as it can be easily substituted in the equation.
say our 2 equations are
2x+4y=10
3x+2y=11
As per our formula x= Num/deno.
now numerator is obtained by cross multiplying (4*11) and subtracting from it the cross product of (2*10)=44-20=24
and denominator is obtained by cross multiplying (4*3) and subtracting from it the cross product of (2*2)=12-4=8
therefore our value for x = Num/Den = 24/8=3
now we can find the value of Y in similar way. however, it will be time consuming . thus we just substitute the value of X in one of the variable.
2x+4y=10
2(3)+4y=10
y=1
therefore we get our two variables x=3,y=1.
hope this helps for quicker calculations.
For those who are curious how to find value of Y in a similar way the method is mentioned below.
i ll just retype the previous equations for better understanding
2x+4y=10
3x+2y=11
again for Y the same formula=Num/ Den ( but the multiplication is slightly different)
now numerator is obtained by cross multiplying (2*11) and subtracting from it the cross product of (3*10)=22-30=-8
and denominator is obtained by cross multiplying (2*2) and subtracting from it the cross product of (4*3)=4-12=-8
thus Y=num/den=-8/-8=1
y=1.
now we can find the value of X, by substituting the value of Y in any equations, as we did above.
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19 Sep 2018, 12:27
Kudos
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Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
