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# Sits and Row

Author Message
Manager
Joined: 29 May 2008
Posts: 110

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17 Jun 2009, 06:25
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 1 sessions

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How many ways can three people sit in a row of five sits if two of the five seats will remain empty?

A) 60
B) 30
C) 20
D) 15
E) 3

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Senior Manager
Joined: 08 Jan 2009
Posts: 310

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17 Jun 2009, 06:43
Three people can select 5 places in 5C3 ways and the can be rotated among themselves in 3! ways

5C3 * 3! = 10 * 6 = 60.
Manager
Joined: 29 May 2008
Posts: 110

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17 Jun 2009, 06:59
It is soooo true those 3 have to stick together "emtpy"

Thank you so much
Intern
Joined: 24 May 2009
Posts: 34

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19 Jun 2009, 19:33
Let $$P_1$$ ,$$P_2$$ , $$P_3$$ = 3 distinct persons
E = an empty seat

Therefore, there are $$P_1$$, $$P_2$$, $$P_3$$, E, E members to be rotated. They're 5! methods to rotate them.

However, there're 2 Es in common. So the answer is $$\frac{5!}{2!}$$ = 60. Agree with tkarthi4u, (A).

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: Sits and Row   [#permalink] 19 Jun 2009, 19:33
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# Sits and Row

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