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Sits and Row

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Manager
Joined: 29 May 2008
Posts: 111

Kudos [?]: 127 [0], given: 0

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17 Jun 2009, 05:25
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Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 1 sessions

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How many ways can three people sit in a row of five sits if two of the five seats will remain empty?

A) 60
B) 30
C) 20
D) 15
E) 3

Kudos [?]: 127 [0], given: 0

Senior Manager
Joined: 08 Jan 2009
Posts: 324

Kudos [?]: 189 [0], given: 5

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17 Jun 2009, 05:43
Three people can select 5 places in 5C3 ways and the can be rotated among themselves in 3! ways

5C3 * 3! = 10 * 6 = 60.

Kudos [?]: 189 [0], given: 5

Manager
Joined: 29 May 2008
Posts: 111

Kudos [?]: 127 [0], given: 0

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17 Jun 2009, 05:59
It is soooo true those 3 have to stick together "emtpy"

Thank you so much

Kudos [?]: 127 [0], given: 0

Intern
Joined: 24 May 2009
Posts: 37

Kudos [?]: 75 [0], given: 4

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19 Jun 2009, 18:33
Let $$P_1$$ ,$$P_2$$ , $$P_3$$ = 3 distinct persons
E = an empty seat

Therefore, there are $$P_1$$, $$P_2$$, $$P_3$$, E, E members to be rotated. They're 5! methods to rotate them.

However, there're 2 Es in common. So the answer is $$\frac{5!}{2!}$$ = 60. Agree with tkarthi4u, (A).

Kudos [?]: 75 [0], given: 4

Re: Sits and Row   [#permalink] 19 Jun 2009, 18:33
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