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30 Dec 2015, 10:49
Kudos
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Hi,
I have an data sufficiency question that I find a smart way to solve in less than 2 minutes. Could you please help..
Mira and Nina can each perform a certain task in m and n hours, respectively.
Ism<n?
(1) Twice the time it would take both Mira and Nina to perform the task together, each working at their respective constant rates, is greater than m.
(2) Twice the time it would take both Mira and Nina to perform the task together, each working at their respective constant rates, is less than n
Its a Rate Time distance Quant problem.
Answer is D
Thanks,
Saket
I have an data sufficiency question that I find a smart way to solve in less than 2 minutes. Could you please help..
Mira and Nina can each perform a certain task in m and n hours, respectively.
Ism<n?
(1) Twice the time it would take both Mira and Nina to perform the task together, each working at their respective constant rates, is greater than m.
(2) Twice the time it would take both Mira and Nina to perform the task together, each working at their respective constant rates, is less than n
Its a Rate Time distance Quant problem.
Answer is D
Thanks,
Saket
30 Dec 2015, 21:30
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Bookmarks
faster2015
Hi Saket,
the Q can be solved in less than 30 secs, if you can play around with the info provided, and algebrically in 1-1 1/2 min ..
lets see the Q..
Q is .. is m<n?
the statements..
(1) Twice the time it would take both Mira and Nina to perform the task together, each working at their respective constant rates, is greater than m.
info:-
the statement can be made to read that time taken combined(M and N) to finish the work twice is greater than work completed once individually by M...
or time taken combined(M and N) to finish the work twice is greater than work completed
this shows M is faster than N... so m<n..
Algebra:-
time taken by both =\(\frac{mn}{(m+n)}\)..
so as per the statement \(\frac{2mn}{(m+n)}>m\)..
so \(\frac{2mn}{(m+n)}-m>0\)
\(\frac{(2mn-m^2-mn)}{(m+n)}>0\)....
or \(\frac{m(n-m)}{(m+n)}>0\)....
so this means ..
if m is positive n>m, and
if m is -ive, m>n..
but m has to be positive, so n>m..
suff
(2) Twice the time it would take both Mira and Nina to perform the task together, each working at their respective constant rates, is less than n
similarly for this statement
Hope it helped
31 Dec 2015, 02:35
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Thank You so much. The Solution you gave is easily understood and I like the multiple approach of solving this question.
Moreover, I had one more simpler problem question but I could not think of a solution to solve this problem using the “Change to the Mean” formula. Could you please help?
Mat gets a $1,000 commission on a big sale. This commission alone raises his aver- age commission by $150. If Mat's new average commission is $400, how many sales has Mat made?
Thanks,
Saket
Moreover, I had one more simpler problem question but I could not think of a solution to solve this problem using the “Change to the Mean” formula. Could you please help?
Mat gets a $1,000 commission on a big sale. This commission alone raises his aver- age commission by $150. If Mat's new average commission is $400, how many sales has Mat made?
Thanks,
Saket
