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08 May 2021, 00:05
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
62% (02:01) correct
38%
(02:13)
wrong
based on 195
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Sofia and Tess will each randomly choose one of the 10 integers from 1 to 10. What is the probability that neither integer chosen will be the square of the other?
A. 0.64
B. 0.72
C. 0.81
D. 0.90
E. 0.95
A. 0.64
B. 0.72
C. 0.81
D. 0.90
E. 0.95
08 May 2021, 01:51
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Total ordered pairs = 10 * 10 = 100
Neither integer chosen will be the square of the other: 1 - integer chosen square of other.
Desired pairs: (1,1),(2,4),(3,9),(4,2),(9,3)
Probability: \(\frac{5 }{100} = 0.05\)
Neither integer chosen will be the square of the other: 1 - 0.05 = 0.95
Answer E
Neither integer chosen will be the square of the other: 1 - integer chosen square of other.
Desired pairs: (1,1),(2,4),(3,9),(4,2),(9,3)
Probability: \(\frac{5 }{100} = 0.05\)
Neither integer chosen will be the square of the other: 1 - 0.05 = 0.95
Answer E
09 May 2021, 09:22
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Given: Sofia and Tess will each randomly choose one of the 10 integers from 1 to 10.
Asked: What is the probability that neither integer chosen will be the square of the other?
Unfavorable ways = {(1,1),(2,4),(4,2),(3,9),(9,3)} : 5 ways
Total ways = 10*10 = 100 ways
Favorable ways = 100 - 5 = 95 ways
Probability that neither integer chosen will be the square of the other = 95/100 = .95
IMO E
Asked: What is the probability that neither integer chosen will be the square of the other?
Unfavorable ways = {(1,1),(2,4),(4,2),(3,9),(9,3)} : 5 ways
Total ways = 10*10 = 100 ways
Favorable ways = 100 - 5 = 95 ways
Probability that neither integer chosen will be the square of the other = 95/100 = .95
IMO E
