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Solve this root

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Manager
Manager
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Joined: 25 May 2009
Posts: 142
Concentration: Finance
GMAT Date: 12-16-2011
Solve this root [#permalink]

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New post 28 Jun 2009, 13:32
00:00
A
B
C
D
E

Difficulty:

(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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\(2(\frac{2sqrt2}{\sqrt{pie}})\)

[Reveal] Spoiler:
\(4\frac{2}{\sqrt{pie}}\)


Please explain, I keep getting \(\frac{4sqrt2}{sqrt(pie)}\)
Senior Manager
Senior Manager
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Joined: 04 Jun 2008
Posts: 286
Re: Solve this root [#permalink]

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New post 28 Jun 2009, 13:46
are u sure this answer is correct? It should be the ans that you are getting
Manager
Manager
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Joined: 25 May 2009
Posts: 142
Concentration: Finance
GMAT Date: 12-16-2011
Re: Solve this root [#permalink]

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New post 28 Jun 2009, 14:33
That's what I thought. Is the OG wrong? Please see the Diagnostic Test Question #22.
Manager
Manager
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Joined: 28 Jan 2004
Posts: 201
Location: India
Re: Solve this root [#permalink]

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New post 28 Jun 2009, 21:42
The OG is right.There is a catch in this question.

Volume of cylinder = Pi * R *R *H
Cylinder is half filled with water,so volume of his much water = Pi * R *R * (h/2) = 36
Now if you calculate,

h *R^2 *Pi = 72
R^2 * Pi = 72/9
R^2 * Pi = 8
R^2 = 8/Pi
or R = Sqrt(8/Pi)
= 2Sqrt(2) / Sqrt(Pi)
So diameter = 4Sqrt(2) / Sqrt(Pi)
Manager
Manager
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Joined: 28 Jan 2004
Posts: 201
Location: India
Re: Solve this root [#permalink]

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New post 28 Jun 2009, 21:45
Oops...my bad I3igDmsu

The answer which you are getting = same as what i calculated = same as in OG (option E).
Manager
Manager
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Joined: 25 May 2009
Posts: 142
Concentration: Finance
GMAT Date: 12-16-2011
Re: Solve this root [#permalink]

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New post 29 Jun 2009, 05:19
Wouldn't \(4sqrt2\) be the same as \(sqrt16=4\)? Why is the answer for the numerator 4(2)?
Re: Solve this root   [#permalink] 29 Jun 2009, 05:19
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Solve this root

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