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Speed problem in gmatprep1

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Speed problem in gmatprep1 [#permalink]

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New post 13 Jul 2009, 09:26
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Hi
This problem appeared in gmatprep1
Distance travlled by a boat upstream is 90 miles and speed is v-3 miles/hr.While going downstream boat has a speed of v+3 miles/hr.If distance travelled upstream and downstream is same and boat takes 1/2 hr more to travle upstream than time for downstream,what is the downstream time?
Can anyone please help me in solving this problem and also any quick fix tips..
Thanks

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Re: Speed problem in gmatprep1 [#permalink]

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New post 13 Jul 2009, 11:35
Here's the solution..
Upstream ( d=90, s = (v-3), t=t1 ) , since \(S = D/T\) or \(T = D/S\) therefore \(t1 = 90/(v-3)\)
Downstream ( d=90, s=(v+3), t=t2 ) , \(t2=90/(v+3)\)

As per the problem, \(t1=t2+ 1/2\) or \(t1-t2=1/2\)
therefore

\((90/(v-3)) -(90/(v+3)) = 1/2\)
Solving this equation we get v = 33
substituting the value of V in the equation for downstream we get \(t2 = 90/(30+3)= 2.5\)
The answer is 2.5

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Re: Speed problem in gmatprep1   [#permalink] 13 Jul 2009, 11:35
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