Steve took 5 history exams during a semester. Each score was

Also got D

1 - We can get the last socre by finding the missing score from avg,

2 - We know the sum of the last two tests is 194, and since test score can't be above 100, the last two tests are greater than 90 so 87 is the median.

OA is D.

As people have said ...

(1) Tells us that the scores on the first 4 exams were 76, 87, 73, and 96, respectively. Average on the last 3 exams was 89 and 3*89 is 267. Subtracting the scores from the 3rd and 4th exam which we were told, 267 - 73 - 96 = 98. So the scores in increasing order were:
73, 76, 87, 96, 98
and the median is 87.
Thus, (1) is sufficient.

(2) Tells us that the scores on the first 3 exams were 76, 87, and 73, respectively. Also we are told that the his average score was 86 and thus the total score of all 5 exams is 86 * 5 = 430. Subtracting the first three exams scores, 430 - 76 - 87 - 73, leaves 194 as the sum of the last two exams scores. Since the highest score possible is 100 there is no possible way to distribute the score across the two exams (i.e. 100/94, 99/95, ...) and get anything other than 87 as the median.
Thus, (2) is sufficient.

OA is D

after doing it I see the answer already posted, but since I did it, I'll just chime in and agree. answer is D.