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# Steve traveled the first 2 hours of his journey at 40 mph an

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Manager
Joined: 22 Sep 2010
Posts: 85
Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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22 Oct 2010, 05:51
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5% (low)

Question Stats:

88% (00:41) correct 12% (13:33) wrong based on 156 sessions

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Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C. 53.33 mph
D. 64 mph
E. 66.67 mph
Manager
Joined: 17 Aug 2010
Posts: 51
Re: Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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22 Oct 2010, 06:17
pzazz12 wrote:
Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C . 53.33 mph
D. 64 mph
E. 66.67 mph

Distance traveled in 2 hours = 2 * 40 = 80 m
Distance traveled in 3 hours = 3 * 80 = 240m

Total distance covered = 240 + 80 = 320m
Total time = 2 + 3 =5 h

Hence avg speed = total distance covered / total time taken

= 320/5 = 64mph

Answer: D
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Re: Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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22 Oct 2010, 06:49
pzazz12 wrote:
Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C . 53.33 mph
D. 64 mph
E. 66.67 mph

$$average \ speed=\frac{total \ distance}{total \ time}$$;

$$total \ distance=2*40+3*8=320$$;

$$total \ time=2+3=5$$;

$$average \ speed=\frac{total \ distance}{total \ time}=\frac{320}{5}=64$$.

Answer: D.
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Intern
Joined: 18 Sep 2010
Posts: 2
Re: Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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22 Oct 2010, 06:52
Rate 40 80 x
Time 2 3 2+3
Distance 80 240 80+240

x = 320/5 = 64
Intern
Joined: 15 May 2010
Posts: 12
Re: Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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22 Oct 2010, 08:25
[D] for sure.
I do not think this qualifies as a 600-700 question, does it?
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Re: Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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12 Mar 2018, 10:11
pzazz12 wrote:
Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C. 53.33 mph
D. 64 mph
E. 66.67 mph

Steve’s total distance was 2 x 40 + 3 x 80 = 80 + 240 = 320 miles.

We can now determine average speed:

Average speed = (total distance)/(total time)

Average speed = 320/5 = 64 mph

Answer: D
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Re: Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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12 Mar 2018, 11:03
pzazz12 wrote:
Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C. 53.33 mph
D. 64 mph
E. 66.67 mph

Avg Speed = $$\frac{d_1 + d_2}{t_1 + t_2}$$

Or, Avg Speed = $$\frac{2*40 + 3*80}{2 + 3}$$

Or, Avg Speed = $$64$$, Answer will be (D)
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Re: Steve traveled the first 2 hours of his journey at 40 mph an [#permalink]

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14 Apr 2018, 23:29
pzazz12 wrote:
Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?

A. 60 mph
B. 56.67 mph
C. 53.33 mph
D. 64 mph
E. 66.67 mph

Avg. speed = Total distance / Total time

= $$\frac{2 * 40 + 3 * 80}{2 + 3}$$

=$$\frac{320}{5}$$

= 64 mph

(D)
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Re: Steve traveled the first 2 hours of his journey at 40 mph an   [#permalink] 14 Apr 2018, 23:29
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# Steve traveled the first 2 hours of his journey at 40 mph an

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