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yangsta8
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E (i.e. 8.x hrs)

Sorry I don't have a short-cut for solving it.
I solved it step by step in a lengthy way.
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yangsta8
Hi All,
Am relatively new to the forums and have been trolling a bit so thought I'd put up my first question.

Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independantly can process the same number of envelopes in 2\(\frac{1}{2}\) hours. If machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take machine B to process 12000 envelopes.

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The OA basically crunches the maths and I'm wondering if anyone can offer a strategy which is simpler

Well, maths is as simple as you think it is. Heres one way you can solve it.
Given A = 6000 env in 3 hours => 2000 in 1 hour.
Given B+C = 6000 in 2 and half hours ie 2400 in 1 hour.
Given A+C = 3000 in one hour. However, we already know that A is 2000 envelopes per hour.
Hence, C must be 1000 envelopes.
Therefore, B must be produce 1400 envelopes per hour. Therefore, for 12000 envelopes, approx. 8 and half hours.

Hope this helps. :)
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yangsta8
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Thanks, I guess the mathematical way is quite simple when laid out that way.
The OA was a little more confusing.



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