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Students in certain group know either English or French or both. If 20

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Students in certain group know either English or French or both. If 20  [#permalink]

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New post Updated on: 10 Jan 2016, 10:27
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Question Stats:

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Students in certain group know either English or French or both. If 20% of those who know English do not know French, and 60% of those who know French know English, what part of the entire group knows both languages?


A) 1/2
B) 12/23
C) 23/35
D) 13/27
E) 1/5

Originally posted by TeymurHajiyev on 10 Jan 2016, 04:22.
Last edited by ENGRTOMBA2018 on 10 Jan 2016, 10:27, edited 1 time in total.
Reformatted the question
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Re: Students in certain group know either English or French or both. If 20  [#permalink]

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New post 10 Jan 2016, 04:43
TeymurHajiyev wrote:
Students in certain group know either English or French or both. If 20% of those who know English do not know French, and 60% of those who know French know English, what part of the group knows both languages?


Sorry guys, for constantly bothering you with this overlapping sets things. I promise, this would be the last one ;-)



Hi,
Again, venn diag would make it easy to comprehend..

let students who Know only english =E..
let students who Know only french =F..
let students who Know both english and french = B..

total =E+F+B..
1) If 20% of those who know English do not know French..
this means that 30% of students knowing english is B..
E=.2(E+B)...
2B=8E..
\(E=B/4\)...(i)

2)60% of those who know French know English
this means that 60% of students knowing French is B.
B=.6(F+B)..
\(F=\frac{4B}{6}\)..(ii)

add values found in (i) and (ii) in total..
so \(Total=E+F+B=\frac{B}{4}+ \frac{4B}{6} + B= \frac{23}{12} * B\)...

so \(\frac{23}{12} * B=T\)...
B=12/23 of total... ans

Doesn't matter .. you can ask till you clear your doubts...
someone will surely answer them
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Re: Students in certain group know either English or French or both. If 20  [#permalink]

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New post 10 Jan 2016, 08:00
2
1
TeymurHajiyev wrote:
Students in certain group know either English or French or both. If 20% of those who know English do not know French, and 60% of those who know French know English, what part of the group knows both languages?


Sorry guys, for constantly bothering you with this overlapping sets things. I promise, this would be the last one ;-)


Couple of points before I delve into your question:

1. Make sure to mention the complete question with all the options.

2. Follow posting guidelines including proper tags for the questions and do make sure to search for your questions before you post a new question.

Refer to the picture below

Attachment:
2016-01-10_10-56-43.jpg
2016-01-10_10-56-43.jpg [ 29.19 KiB | Viewed 1276 times ]


Text in black is assumed/given and text in red is calculated.

From the common area (both english and french) ---> 0.8E = 0.6F ---> 4E=3F ...(1)

Additionally, T=E+0.4F = E+(8/15)E = (23/15)E ....(2)

Additionally, fraction of total group that knows both English and French = 0.8E = 0.8*(15/23) T = (12/23) T or just less than 50% of the total students.

Hope this helps.
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Students in certain group know either English or French or both. If 20  [#permalink]

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New post 25 Nov 2017, 12:16
chetan2u wrote:
TeymurHajiyev wrote:
Students in certain group know either English or French or both. If 20% of those who know English do not know French, and 60% of those who know French know English, what part of the group knows both languages?


Sorry guys, for constantly bothering you with this overlapping sets things. I promise, this would be the last one ;-)



Hi,
Again, venn diag would make it easy to comprehend..

let students who Know only english =E..
let students who Know only french =F..
let students who Know both english and french = B..

total =E+F+B..
1) If 20% of those who know English do not know French..
this means that 30% of students knowing english is B..
E=.2(E+B)...
2B=8E..
\(E=B/4\)...(i)

2)60% of those who know French know English
this means that 60% of students knowing French is B.
B=.6(F+B)..
\(F=\frac{4B}{6}\)..(ii)

add values found in (i) and (ii) in total..
so \(Total=E+F+B=\frac{B}{4}+ \frac{4B}{6} + B= \frac{23}{12} * B\)...

so \(\frac{23}{12} * B=T\)...
B=12/23 of total... ans

Doesn't matter .. you can ask till you clear your doubts...
someone will surely answer them


chetan2u
hi

maybe it is very obvious, but I am in trouble
please see as follows

20% of those who know English do not know French, that means 0.2E knows only English.
so, a total of (0.2E + B) knows English

thus, E = 0.2E + B

please spot the wrong above :sad:

secondly, 60% of those who know French know English,
so,
B= 0.6F + 0.8E

please spot the wrong above :sad:

thanks in advance, man
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Students in certain group know either English or French or both. If 20 &nbs [#permalink] 25 Nov 2017, 12:16
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