Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 1612:00 PM EDT
-11:59 PM EDT
You’re first to know: Save $200 on GMAT prep starting tomorrow, 4/13. Get 6 official practice tests and study with real questions. Be ready to save!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
02 Jul 2019, 04:14
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
66% (01:25) correct
34%
(01:36)
wrong
based on 198
sessions
History
Date
Time
Result
Not Attempted Yet
Suppose a box contains 20 balls. Ten balls are white and marked with the integers 1–10. The other 10 balls are red and marked with the integers 11–20. If one ball is selected, what is the probability that the ball will be white OR will be marked with an even number?
A. 1/4
B. 1/2
C. 3/4
D. 4/5
E. 9/10
A. 1/4
B. 1/2
C. 3/4
D. 4/5
E. 9/10
02 Jul 2019, 04:25
Kudos
Bookmarks
Bunuel
# of favorable outcomes = 10 (white ball) + 5 (even red balls) = 15
# of total outcomes = 20
Probability = 15 /20 = 3/4
IMO C
02 Jul 2019, 05:03
Kudos
Bookmarks
# of white balls = 10
# of even number = 10
# of even numbers which are on white balls( overlapping/repitative set) = 5
Total outcomes = 20
Probability = (10/20+ 10/20 - 5/20) = 3/4
IMO C
Hit Kudos if you like my solution.
# of even number = 10
# of even numbers which are on white balls( overlapping/repitative set) = 5
Total outcomes = 20
Probability = (10/20+ 10/20 - 5/20) = 3/4
IMO C
Hit Kudos if you like my solution.
