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Difficulty:
45%
(medium)
Question Stats:
76% (02:25) correct
24%
(02:37)
wrong
based on 285
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Sylvia is driving at 48 miles/hr and her husband Kal is driving at 55 miles/hr. If he starts off from home 45 minutes after she has left, how long would he take to catch up with her on the journey if they’re both taking the same route?
A. 5 hours 2 minutes
B. 5 hours 4 minutes
C. 5 hours 6 minutes
D. 5 hours 8 minutes
E. 5 hours 10 minutes
A. 5 hours 2 minutes
B. 5 hours 4 minutes
C. 5 hours 6 minutes
D. 5 hours 8 minutes
E. 5 hours 10 minutes
07 Aug 2024, 06:49
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Going to do my best and give my first ever explanation.
D = R x T
Silvia D = 48 mph x (t + 3/4) ====> (Note: 45 mins is converted to 3/4 to respect the units)
Kal D = 55mph x (t)
Given they both travelled the same distance, let the 2 equations equal each other.
48t + 144/4 = 55t
36=7t
t=36/7
t= 5 hours and 1/7 hour
We know that 1/6 is 10 mins so 1/7 has to be slightly less than 10, therefore answer D 5 hours and 8 mins.
D = R x T
Silvia D = 48 mph x (t + 3/4) ====> (Note: 45 mins is converted to 3/4 to respect the units)
Kal D = 55mph x (t)
Given they both travelled the same distance, let the 2 equations equal each other.
48t + 144/4 = 55t
36=7t
t=36/7
t= 5 hours and 1/7 hour
We know that 1/6 is 10 mins so 1/7 has to be slightly less than 10, therefore answer D 5 hours and 8 mins.
10 Aug 2024, 03:12
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In 45 mins (= (45/60) hours), Sylvia covered D= S x T
D = (48x45)/60 = 36 miles
Now for Kal to catch up with Sylvia, we consider relative speed of the two persons.
Relative speed (moving in same direction), RS= Speed of Kal- Speed of Syl = 55-48 = 7 mph
Time taken by Kal to catch up with Sylvia, T = D/RS
T= 36/7 = 5 (1/7) hrs = 5 hours and 8 minutes
Option D
D = (48x45)/60 = 36 miles
Now for Kal to catch up with Sylvia, we consider relative speed of the two persons.
Relative speed (moving in same direction), RS= Speed of Kal- Speed of Syl = 55-48 = 7 mph
Time taken by Kal to catch up with Sylvia, T = D/RS
T= 36/7 = 5 (1/7) hrs = 5 hours and 8 minutes
Option D
