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# Tanks X and Y contain 500 and 200 gallons of water

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Tanks X and Y contain 500 and 200 gallons of water [#permalink]

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06 Nov 2006, 06:55
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Tanks X and Y contain 500 and 200 gallons of water respectively. Water is being pumped out of tank X at a rate of K gallons per minute and water is being added at M gallons per minute. How much time will elapse before the two tanks contain equal amounts of water?

1) 5/(M+K) hours
2) 6*(M+K) hours
3) 300/(M+K) hours
4) 300/(M-K) hours
5) 60/(M-K) hours

Last edited by uvs_mba on 06 Nov 2006, 23:51, edited 1 time in total.
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06 Nov 2006, 09:36
Here is the equation

500 - K*T = 200 + M*T

T * (M+K) = 300

T = 300/ (M+K)

so T= 300/(M+K)*60 = 5/M+K

Last edited by Damager on 06 Nov 2006, 09:51, edited 1 time in total.
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06 Nov 2006, 09:48
damager got the ans in mins...
divide that by 60 to arrive in hours..

choice a
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06 Nov 2006, 10:32
haha! I made the same mistake and then I looked at it, lol, was just curious how many people overlook that. lol! By the way thanks a lot for the answer. Yes the answer is A, you guys are great
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06 Nov 2006, 21:00
This part of the question "water is being added to M gallons per minute" has typo. Please correct it. Thanks.
06 Nov 2006, 21:00
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