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1894
How without knowing the share quantity can we answer question no. 3 ?
We are given equal number of shares, and A does exactly the opposite of B. So if A makes a profit of x, B will make a loss of x. Hence, overall result will be no profit and no loss.­
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chetan2u
1894
How without knowing the share quantity can we answer question no. 3 ?
We are given equal number of shares, and A does exactly the opposite of B. So if A makes a profit of x, B will make a loss of x. Hence, overall result will be no profit and no loss.­
I think 1894 is talking about part 1 of q3. While we know the profit per share on each day. We can't answer on which day A made more profit (#shares x profit pershare) since we are not told what was the quantity traded on day 1 vs day 2. 
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chetan2u
1894
How without knowing the share quantity can we answer question no. 3 ?
We are given equal number of shares, and A does exactly the opposite of B. So if A makes a profit of x, B will make a loss of x. Hence, overall result will be no profit and no loss.­
I think 1894 is talking about part 1 of q3. While we know the profit per share on each day. We can't answer on which day A made more profit (#shares x profit pershare) since we are not told what was the quantity traded on day 1 vs day 2. 
­Hi, since the machines are programmed to sell certain shares on each day, it would be same quantity. But yes, it could be made more clear or turned to per share.
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Hi how to answer q1?
[quote][/quote] The maximum % increase in price of share on Day 2 compared to Day 1 at exactly the same time on the two days was at

is it to compare day 2 and day 1 at each time? such as below
time day 1. day 2
09.00 12->11 13->15
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Some language in the question was updated for readability.
Thank you.
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Q.1 The maximum % increase in price of share on Day 2 compared to Day 1 at exactly the same time on the two days was at:-
We have to look at the increase on Day 2 when compared to same time on day 1. So, at 0900h on day2 over 0900h on day 1.
Scan the graph for the maximum gap between two lines where yellow line is the lower line.
Two such points are at 1000h and 1500h. But we are looking at maximum % increase, so look which point has lower value on day 1 as that will be the reference point on which increase is made.
increase of 50 on 10 would give higher % than increase of 50 on 20. Hence, 1000h is the answer.


Q.2. For each of the following statements, select Supported if, according to the information provided, the statement is true. Otherwise select Not Supported.
(a) The ATS A gives a profit on each day.
The ATS A buys shares at 0900h and sells half of it at 1200h and 1500h, so they are sold at an average of the prices at these two times.
Day 1: Buy - 120; sell - (120+140)/2 or 130...Hence profit of $10 per share
Day 2: Buy - 130; sell - (120+160)/2 or 140...Hence profit of $10 per share
Supported

(b) The profit per share on both the days by either of the ATS giving profit is the same.
ATS A gives profit on each day and is equal to $10 on each day. Hence, supported.

(c) The range of the price per share is more on Day 1.
The lower point of each line is at 110 but the higher point on Day 2 id 10 more than tha on day 1. Hence, the range will be higher on Day 2.
Not supported


Q.3. For each of the following statements, select Yes if the question can be answered based on the information in the passage. Otherwise, select No.
(a) On which day did ATS A give more profit for each share sold?
ATS A gave the same profit of $10 per share. So, YES

(b) What is the total loss incurred by ATS B over the two days?
We do not know the exact number of shares purchased by the ATSs, so NO.

(c) If there were equal shares traded at 0900h on each day by ATS A and ATS B, what was the combined profit/loss over two days.
The activity done by A and B is opposite of each other at exactly the same time and for same amount, so the overall profit will be Zero...YES­
­in Q3 - Part 1, shouldn't the option be "No", since, ATS A generates equal profit per share ($10)? Hence, we can't confirm which day gave more profit. 

I was thinking along the above logic, thus opted for "No".

Please suggest gaps in my understanding. 

Thanks for the series. Extremely helpful.
Cheers!
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chetan2u

For Question 2, Statement second, "The profit per share on both days from either ATS is the same"

How this is supported by the given information?, as we can see that the ATS B will results in a loss for the given days.
From ATS A - Profit of 10/share
ATS B - Loss of 10/share
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MakSha
chetan2u
Q.1 The maximum % increase in price of share on Day 2 compared to Day 1 at exactly the same time on the two days was at:-
We have to look at the increase on Day 2 when compared to same time on day 1. So, at 0900h on day2 over 0900h on day 1.
Scan the graph for the maximum gap between two lines where yellow line is the lower line.
Two such points are at 1000h and 1500h. But we are looking at maximum % increase, so look which point has lower value on day 1 as that will be the reference point on which increase is made.
increase of 50 on 10 would give higher % than increase of 50 on 20. Hence, 1000h is the answer.


Q.2. For each of the following statements, select Supported if, according to the information provided, the statement is true. Otherwise select Not Supported.
(a) The ATS A gives a profit on each day.
The ATS A buys shares at 0900h and sells half of it at 1200h and 1500h, so they are sold at an average of the prices at these two times.
Day 1: Buy - 120; sell - (120+140)/2 or 130...Hence profit of $10 per share
Day 2: Buy - 130; sell - (120+160)/2 or 140...Hence profit of $10 per share
Supported

(b) The profit per share on both the days by either of the ATS giving profit is the same.
ATS A gives profit on each day and is equal to $10 on each day. Hence, supported.

(c) The range of the price per share is more on Day 1.
The lower point of each line is at 110 but the higher point on Day 2 id 10 more than tha on day 1. Hence, the range will be higher on Day 2.
Not supported


Q.3. For each of the following statements, select Yes if the question can be answered based on the information in the passage. Otherwise, select No.
(a) On which day did ATS A give more profit for each share sold?
ATS A gave the same profit of $10 per share. So, YES

(b) What is the total loss incurred by ATS B over the two days?
We do not know the exact number of shares purchased by the ATSs, so NO.

(c) If there were equal shares traded at 0900h on each day by ATS A and ATS B, what was the combined profit/loss over two days.
The activity done by A and B is opposite of each other at exactly the same time and for same amount, so the overall profit will be Zero...YES­
­in Q3 - Part 1, shouldn't the option be "No", since, ATS A generates equal profit per share ($10)? Hence, we can't confirm which day gave more profit. 

I was thinking along the above logic, thus opted for "No".

Please suggest gaps in my understanding. 

Thanks for the series. Extremely helpful.
Cheers!
­Hi

If you know the values, you can answer in any way. If both are equal, then answer would be both days.
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Keshav1404
chetan2u

For Question 2, Statement second, "The profit per share on both days from either ATS is the same"

How this is supported by the given information?, as we can see that the ATS B will results in a loss for the given days.
From ATS A - Profit of 10/share
ATS B - Loss of 10/share
­Even I think the same chetan2u , Also....

(c) The range of the price per share is more on Day 1.
The lower point of each line is at 110 but the higher point on Day 2 id 10 more than tha on day 1. Hence, the range will be higher on Day 2.
Not supported


How is it Higher on Day 2, when Day 1 is reaching till 160, where as Day 2 Max value is 150.
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ShilpiAgnihotrii
Keshav1404
chetan2u

For Question 2, Statement second, "The profit per share on both days from either ATS is the same"

How this is supported by the given information?, as we can see that the ATS B will results in a loss for the given days.
From ATS A - Profit of 10/share
ATS B - Loss of 10/share
­Even I think the same chetan2u , Also....

(c) The range of the price per share is more on Day 1.
The lower point of each line is at 110 but the higher point on Day 2 id 10 more than tha on day 1. Hence, the range will be higher on Day 2.
Not supported


How is it Higher on Day 2, when Day 1 is reaching till 160, where as Day 2 Max value is 150.

The blue line has the higher range and it gives price fluctuation on day 2.

You are most probably taking day 1 as day 2.

Posted from my mobile device
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chetan2u
ShilpiAgnihotrii
Keshav1404
chetan2u

For Question 2, Statement second, "The profit per share on both days from either ATS is the same"

How this is supported by the given information?, as we can see that the ATS B will results in a loss for the given days.
From ATS A - Profit of 10/share
ATS B - Loss of 10/share
­Even I think the same chetan2u , Also....

(c) The range of the price per share is more on Day 1.
The lower point of each line is at 110 but the higher point on Day 2 id 10 more than tha on day 1. Hence, the range will be higher on Day 2.
Not supported


How is it Higher on Day 2, when Day 1 is reaching till 160, where as Day 2 Max value is 150.
The blue line has the higher range and it gives price fluctuation on day 2.

You are most probably taking day 1 as day 2.

Posted from my mobile device
­Rightly pointed out my mistake chetan2u :) thanks again!
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To know the combined profit we need to sum the individual profits but there is no information on that. ATS A buys and haven't sold to make profit and ATS B sells but no information purchasing price. So how can we possibly know the profit?
chetan2u
Q.1 The maximum % increase in price of share on Day 2 compared to Day 1 at exactly the same time on the two days was at:-
We have to look at the increase on Day 2 when compared to same time on day 1. So, at 0900h on day2 over 0900h on day 1.
Scan the graph for the maximum gap between two lines where yellow line is the lower line.
Two such points are at 1000h and 1500h. But we are looking at maximum % increase, so look which point has lower value on day 1 as that will be the reference point on which increase is made.
increase of 50 on 10 would give higher % than increase of 50 on 20. Hence, 1000h is the answer.


Q.2. For each of the following statements, select Supported if, according to the information provided, the statement is true. Otherwise select Not Supported.
(a) The ATS A gives a profit on each day.
The ATS A buys shares at 0900h and sells half of it at 1200h and 1500h, so they are sold at an average of the prices at these two times.
Day 1: Buy - 120; sell - (120+140)/2 or 130...Hence profit of $10 per share
Day 2: Buy - 130; sell - (120+160)/2 or 140...Hence profit of $10 per share
Supported

(b) The profit per share on both the days by either of the ATS giving profit is the same.
ATS A gives profit on each day and is equal to $10 on each day. Hence, supported.

(c) The range of the price per share is more on Day 1.
The lower point of each line is at 110 but the higher point on Day 2 id 10 more than tha on day 1. Hence, the range will be higher on Day 2.
Not supported


Q.3. For each of the following statements, select Yes if the question can be answered based on the information in the passage. Otherwise, select No.
(a) On which day did ATS A give more profit for each share sold?
ATS A gave the same profit of $10 per share. So, YES

(b) What is the total loss incurred by ATS B over the two days?
We do not know the exact number of shares purchased by the ATSs, so NO.

(c) If there were equal shares traded at 0900h on each day by ATS A and ATS B, what was the combined profit/loss over two days.
The activity done by A and B is opposite of each other at exactly the same time and for same amount, so the overall profit will be Zero...YES­
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