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Tek has two routes that he normally takes when he drives to work. He a

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Bunuel
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Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   10 Apr 2018, 06:49
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Tek has two routes that he normally takes when he drives to work. He always drives the same speed regardless of which route he takes. What is the difference in the distances to and from work between route 1 and route 2?

(1) It takes one hour for Tek to drive round-trip to and from work using route 1.
(2) It takes 40 minutes for Tek to drive round-trip to and from work using route 2.
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varundixitmro2512
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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   10 Apr 2018, 13:17
Speed is required to calculate difference in distances

So IMO E

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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   10 Apr 2018, 17:51
But why is speed required? Because in calculus we have these two definitions : 1) speed is directly proportional to distance when time is constant and 2) speed is inversely proportional to time when distance is constant. You need at least two of the variables to solve for the third. The interesting thing here is that the speed is the same for both routes, so you actually know the speed. It can be whatever you want as long as it’s the same for both routes. The question is not what are the differences rather what is the difference in distances.


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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   10 Apr 2018, 18:39
Logicallt it should be E.
It is asking for a value. Since speed is constant, we have 2V2E. But still, the difference still differs by manipulating the numbers.

*drunk approach*

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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   11 Apr 2018, 02:11
Ans should be E
For both cases
V is same
V = S1* /60
V = S2 / 40
You determine the ration between two distance
Not their exact difference


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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   11 Apr 2018, 06:00
I think it's because we're asked for an actual amount here. I interpreted the difference in distance as D_2 - D_1. Given 1) and 2), the difference in distance is going to be much larger if he's traveling 100 mph vs. if he's traveling 25 mph

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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   11 Apr 2018, 07:57
Should be E,

D2-D1 = Speed (60-40) , need to know speed for cal D2-D1
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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   14 Apr 2018, 13:25
The distance relationship is 2/3. This is essentially what the people who answered E above are saying. Route 2 is 2/3 the distance of Route 1. The question specially asks what is the difference between the two distances. Not what the value of the distances are. Plug in any speed in the formulae above and you will see the answer to the equation is always 2/3.


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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   19 Apr 2018, 04:43
D1=s1*60
D2=s1*40

D1-D2=s1*20

So E

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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink] New post   24 Nov 2018, 00:15
here speed is constant hence time is directly proportional to distance
statement 1 - insuff
statement 2 - insuf
combining ratio is 60:40 but we dont know the multiplying factor hence E
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Re: Tek has two routes that he normally takes when he drives to work. He a [#permalink]
24 Nov 2018, 00:15
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