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Ten slips of paper, numbered 1 through 10, are placed in a

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Manager
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Ten slips of paper, numbered 1 through 10, are placed in a [#permalink]

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New post 05 Sep 2008, 22:12
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Ten slips of paper, numbered 1 through 10, are placed in a bag. If three slips are chosen at random from the bag and one of the slips chosen is numbered 7, what is the sum of the numbers on the three slips of paper?

(1) The sum of two of the numbers is 16
(2) The sum of two of the numbers is 14

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Director
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Re: Zumit DS 008 [#permalink]

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New post 05 Sep 2008, 22:19
dancinggeometry wrote:
Ten slips of paper, numbered 1 through 10, are placed in a bag. If three slips are chosen at random from the bag and one of the slips chosen is numbered 7, what is the sum of the numbers on the three slips of paper?

(1) The sum of two of the numbers is 16
(2) The sum of two of the numbers is 14


B

The sum of the "other" 2 numbers is 14, plus 7 = 21

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VP
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Re: Zumit DS 008 [#permalink]

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New post 05 Sep 2008, 22:33
dancinggeometry wrote:
Ten slips of paper, numbered 1 through 10, are placed in a bag. If three slips are chosen at random from the bag and one of the slips chosen is numbered 7, what is the sum of the numbers on the three slips of paper?

(1) The sum of two of the numbers is 16
(2) The sum of two of the numbers is 14


Very tricky question!!
(1) 16 can be 7+9 or 6+10 hence sum can be 7+9+some unknown which can be any of the rest hence INSUFFI

(2)14 will be sum of any numbers other than 7 since 7,7 cannot be numbers only one slip is numbered 7 => 7+14 =21 is the sum ANSWERS
SUFFI

IMO B
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Re: Zumit DS 008   [#permalink] 05 Sep 2008, 22:33
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Ten slips of paper, numbered 1 through 10, are placed in a

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