Hi,
My solution:
Please note
() - not possible
There are three bags with 4 sticks each:
(1, 2, 3, 4), (1, 2, 3, 4) & (1, 2, 3, 4), Now from each bag one stick has to be chosen.
Case 1: When all sticks are of same lenght (1, 1, 1), (2, 2, 2), (3, 3, 3) or (4, 4, 4)
4 possibilities.
Case 2: When two are of same lenght, and checking the property of trangles such that \(|a-b|<c<a+b\)
(1, 1, 2) (1, 2, 2)
(1, 1, 3) (1, 3, 3)
(1, 1, 4) (1, 4, 4) (2, 2, 3) (2, 3, 3)
(2, 2, 4) (2, 4, 4) (3, 3, 4) (3, 4, 4)
8 possibilities;
each possible case can be drawn in different order: thus 8*3!/2!=24
Case 3: When all are different;
(1, 2, 3) (1, 2, 4) (1, 3, 4) (2, 3, 4),
can be drawn in 3! ways = 6
Considering all above cases: 4+24+6 = 34 ways in which sticks can be drawn to form a triangle.
Total ways = 4C1*4C1*4C1=64
Number of ways when stick is drawn and no triangle is formed = 64-34=30
Probability = 30/64 = 15/32
Answer (C).