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Updated on: 08 Nov 2023, 03:35
Originally posted by felippemed on 26 Sep 2016, 18:50.
Last edited by Bunuel on 08 Nov 2023, 03:35, edited 4 times in total.
Last edited by Bunuel on 08 Nov 2023, 03:35, edited 4 times in total.
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A
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The age of certain granite rocks found in northwestern Canada is approximately \(1.2×10^{17}\) seconds. Which of the following is closest to the age of these rocks, in years? (1 year is approximately \(3.2 × 10^7\) seconds.)
(A) \(3.8*10^9\)
(B) \(5.9*10^9\)
(C) \(2.0*10^{10}\)
(D) \(2.0*10^{11}\)
(E) \(3.8*10^{11}\)
PS01780
(A) \(3.8*10^9\)
(B) \(5.9*10^9\)
(C) \(2.0*10^{10}\)
(D) \(2.0*10^{11}\)
(E) \(3.8*10^{11}\)
PS01780
28 Sep 2016, 01:19
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Very simple one.
We are given \(1 year = 3.2 * 10^7 secs\)
or \(1 sec = 1 / (3.2 * 10^7)\)
Now, given seconds = \(1.2∗10^17\)
We can say \(1.2∗10^17\) = \((1.2∗10^17)/ (3.2 * 10^7)\) = \(3.8∗10^9\)
Hence , A
We are given \(1 year = 3.2 * 10^7 secs\)
or \(1 sec = 1 / (3.2 * 10^7)\)
Now, given seconds = \(1.2∗10^17\)
We can say \(1.2∗10^17\) = \((1.2∗10^17)/ (3.2 * 10^7)\) = \(3.8∗10^9\)
Hence , A
16 Sep 2019, 08:39
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felippemed
The age of certain granite rocks found in northwestern Canada is approximately \(1.2*10^{17}\) seconds. Which of the following is the closest to the age of theses rocks in years? (1 year is approximately \(3.2*10^7 seconds\).)
a) \(3.8*10^9\)
b) \(5.9*10^9\)
c) \(2.0*10^{10}\)
d) \(2.0*10^{11}\)
e) \(3.8*10^{11}\)
a) \(3.8*10^9\)
b) \(5.9*10^9\)
c) \(2.0*10^{10}\)
d) \(2.0*10^{11}\)
e) \(3.8*10^{11}\)
The age of certain granite rocks found in northwestern Canada is approximately \(1.2*10^{17}\) seconds. Which of the following is the closest to the age of theses rocks in years? (1 year is approximately \(3.2*10^7 seconds\).)
Age in years = 12*10^{16}/3.2*10^7 = 3.8 * 10^9 years
IMO A
