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# The area of field A is 30% greater than that of field B

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Re: The area of field A is 30% greater than that of field B [#permalink]
benejo wrote:
The area of field A is 30% greater than that of field B, and 35% less than that of field C. The area of C is what percent greater than the area of field B?

A. 25%
B. 50%
C. 53,8%
D. 100%
E. 200%

We can let the area of field B = n and thus the area of field A = 1.3n.

Since 1.3n is 35% less than the area of field C, we can create the equation:

1.3n = 0.65C

1.3n/0.65 = C

130n/65 = C

2n = C

We now can determine the area of C is what percent greater than the area of field B:

(2n - n)/n x 100 = 1 x 100 = 100 percent

Alternate Solution:

Let’s let the area of field B to be 100. Since area of field A is 30% greater than the area of field B, area of field A is 1.3 x 100 = 130. Let c denote the area of field C. Since area of field A is 35% less than field C, we must have

0.65c = 130

c - 130/0.65 = 200

Thus, the area of field C is [(200 - 100)/100] x 100 = 100% greater than the area of field A.

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Re: The area of field A is 30% greater than that of field B [#permalink]
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Re: The area of field A is 30% greater than that of field B [#permalink]
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