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The areas of faces A, B, and C of the rectangular solid shown in the a

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Director
Joined: 06 Jan 2015
Posts: 732
Own Kudos [?]: 1600 [0]
Given Kudos: 579
Location: India
Concentration: Operations, Finance
GPA: 3.35
WE:Information Technology (Computer Software)
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
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Own Kudos [?]: 17024 [0]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: The areas of faces A, B, and C of the rectangular solid shown in the a [#permalink]
Expert Reply
=>

Let $$a$$ and $$b$$ be the edges of face $$A$$, and let $$b$$ and $$c$$ be the edges of face $$B$$. Then the edges of face $$C$$ are $$a$$ and $$c$$. Moreover, the volume of the solid is $$abc$$. Now,
$$ab = 12$$, $$bc = 15$$ and $$ca = 20$$.
Multiplying these together yields
$$(ab)(bc)(ca) = a^2b^2c^2 = (abc)^2 = 12*15*20 = 3600 = 60^2$$
So $$abc = 60$$.
Therefore, the answer is C.

Answer: C
Re: The areas of faces A, B, and C of the rectangular solid shown in the a [#permalink]
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