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clciotola
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The average (arithmetic man) of three integers a, b, and c i Updated on: 24 Feb 2022, 11:53
Originally posted by clciotola on 21 May 2013, 07:07.
Last edited by GMATNinja on 24 Feb 2022, 11:53, edited 2 times in total.
Renamed the topic and edited the question.
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79% (01:07) correct 21% (01:26) wrong based on 576 sessions

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The average (arithmetic mean) of three integers a, b, and c is exactly twice the median. If a < b < c and a = 0, what is the value of c/b?

A. 2
B. 3
C. 4
D. 5
E. Cannot be determined from the information given.
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D
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Bunuel
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The average (arithmetic man) of three integers a, b, and c i 21 May 2013, 07:15
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clciotola
The average (arithmetic man) of three integers a, b, and c is exactly twice the median. If a < b < c and a = 0, what is the value of c/b?

A. 2
B. 3
C. 4
D. 5
E. Cannot be determined from the information given.
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The average of three integers a, b, and c is exactly twice the median --> (a+b+c)/3=2b --> since a=0, then (0+b+c)/3=2b --> c=5b --> c/b=5.

Answer: D.
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The average (arithmetic man) of three integers a, b, and c i 02 Jun 2018, 03:53
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Bunuel
clciotola
The average (arithmetic man) of three integers a, b, and c is exactly twice the median. If a < b < c and a = 0, what is the value of c/b?

A. 2
B. 3
C. 4
D. 5
E. Cannot be determined from the information given.

The average of three integers a, b, and c is exactly twice the median --> (a+b+c)/3=2b --> since a=0, then (0+b+c)/3=2b --> c=5b --> c/b=5.

Answer: D.
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Hey pushpitkc

do you think my solution is correct and reliable ? :) or perhaps i was lucky :-)

i simply plugged in numbers

\(\frac{0+1+5}{3} = 2\)

\(\frac{5}{1}= 5\)

thank you :-)
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The average (arithmetic man) of three integers a, b, and c i 02 Jun 2018, 05:42
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dave13
Bunuel
clciotola
The average (arithmetic man) of three integers a, b, and c is exactly twice the median. If a < b < c and a = 0, what is the value of c/b?

A. 2
B. 3
C. 4
D. 5
E. Cannot be determined from the information given.

The average of three integers a, b, and c is exactly twice the median --> (a+b+c)/3=2b --> since a=0, then (0+b+c)/3=2b --> c=5b --> c/b=5.

Answer: D.


Hey pushpitkc

do you think my solution is correct and reliable ? :) or perhaps i was lucky :-)

i simply plugged in numbers

\(\frac{0+1+5}{3} = 2\)

\(\frac{5}{1}= 5\)

thank you :-)
Show more


Hi dave13

Unfortunately, your method is wrong - you just got lucky!

Try plugging a different set of numbers - a=0,b=2,c=4.
Here, the average is still 2, but \(\frac{c}{b} = 2\) :)

Hope this helps you!
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The average (arithmetic man) of three integers a, b, and c i 03 Jun 2018, 05:30
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(a+b+c)/3= 2*b
c=5b
c/b= 5
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The average (arithmetic man) of three integers a, b, and c i 04 Dec 2025, 04:45
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