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The average (arithmetic mean) ages, in years, of the people in group A

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The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post 26 Nov 2018, 23:34
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The average (arithmetic mean) ages, in years, of the people in group A and group B are 41 and 36, respectively. The average age, in years, of the people in the two groups combined is 38. If there are no people in both group A and group B, what fraction of the people in the two groups combined are in group B?

A. 2/5
B. 1/2
C. 3/5
D. 2/3
E. 3/4

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Re: The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post 27 Nov 2018, 04:58
Bunuel wrote:
The average (arithmetic mean) ages, in years, of the people in group A and group B are 41 and 36, respectively. The average age, in years, of the people in the two groups combined is 38. If there are no people in both group A and group B, what fraction of the people in the two groups combined are in group B?

A. 2/5
B. 1/2
C. 3/5
D. 2/3
E. 3/4



using allegation method:

41 - 38 = 3

36 - 38 = 2. negative sign must be ignored.

Ratio of the people A and B respectively : 2: 3.

fraction required : 3/ 5.

C is the correct answer.
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The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post Updated on: 28 Nov 2018, 06:07
Bunuel wrote:
The average (arithmetic mean) ages, in years, of the people in group A and group B are 41 and 36, respectively. The average age, in years, of the people in the two groups combined is 38. If there are no people in both group A and group B, what fraction of the people in the two groups combined are in group B?

A. 2/5
B. 1/2
C. 3/5
D. 2/3
E. 3/4



GMATinsight :

Sir how to solve this question ? can this be solved using venn diagram?
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Originally posted by Archit3110 on 27 Nov 2018, 10:02.
Last edited by Archit3110 on 28 Nov 2018, 06:07, edited 2 times in total.
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Re: The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post 28 Nov 2018, 05:21
Bunuel wrote:
The average (arithmetic mean) ages, in years, of the people in group A and group B are 41 and 36, respectively. The average age, in years, of the people in the two groups combined is 38. If there are no people in both group A and group B, what fraction of the people in the two groups combined are in group B?

A. 2/5
B. 1/2
C. 3/5
D. 2/3
E. 3/4


selim

I did not understand the 2nd half the question. Could you please elaborate on it?
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Re: The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post 28 Nov 2018, 08:09
Even i did not get the second part of question. Bunuel could you please explain it.
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Re: The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post 28 Nov 2018, 08:51
1
ParthSanghavi wrote:
Bunuel wrote:
The average (arithmetic mean) ages, in years, of the people in group A and group B are 41 and 36, respectively. The average age, in years, of the people in the two groups combined is 38. If there are no people in both group A and group B, what fraction of the people in the two groups combined are in group B?

A. 2/5
B. 1/2
C. 3/5
D. 2/3
E. 3/4


selim

I did not understand the 2nd half the question. Could you please elaborate on it?



**No people belong to both group.

***we are looking for fraction

*** what fraction of the people in the two groups combined are in group B

Mark these color parts.

In simple words we are looking for the number of people belong to Group B out of all the people who belong to Both A and B.

\(\frac{B}{A + B}\)
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Re: The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post 28 Nov 2018, 13:49
selim wrote:
Bunuel wrote:
The average (arithmetic mean) ages, in years, of the people in group A and group B are 41 and 36, respectively. The average age, in years, of the people in the two groups combined is 38. If there are no people in both group A and group B, what fraction of the people in the two groups combined are in group B?

A. 2/5
B. 1/2
C. 3/5
D. 2/3
E. 3/4



using allegation method:

41 - 38 = 3

36 - 38 = 2. negative sign must be ignored.

Ratio of the people A and B respectively : 2: 3.

fraction required : 3/ 5.

C is the correct answer.



selim if A = 41 - 38 = 3 and B = 36 - 38 = 2.

the why ratio is 3/5 and not 2/5 ?
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The average (arithmetic mean) ages, in years, of the people in group A  [#permalink]

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New post 28 Nov 2018, 15:24
dave13 wrote:
selim wrote:
Bunuel wrote:
The average (arithmetic mean) ages, in years, of the people in group A and group B are 41 and 36, respectively. The average age, in years, of the people in the two groups combined is 38. If there are no people in both group A and group B, what fraction of the people in the two groups combined are in group B?

A. 2/5
B. 1/2
C. 3/5
D. 2/3
E. 3/4



using allegation method:

41 - 38 = 3

36 - 38 = 2. negative sign must be ignored.

Ratio of the people A and B respectively : 2: 3.

fraction required : 3/ 5.

C is the correct answer.



selim if A = 41 - 38 = 3 and B = 36 - 38 = 2.

the why ratio is 3/5 and not 2/5 ?



coz 2 persons belong to group A. but we are looking for B . \(\frac{B}{A+B}\)
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The average (arithmetic mean) ages, in years, of the people in group A &nbs [#permalink] 28 Nov 2018, 15:24
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