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The average (arithmetic mean) amount of money that a group of four fri

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The average (arithmetic mean) amount of money that a group of four fri  [#permalink]

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New post 22 Aug 2018, 19:35
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Difficulty:

  35% (medium)

Question Stats:

77% (02:05) correct 23% (01:43) wrong based on 25 sessions

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The average (arithmetic mean) amount of money that a group of four friends pays for rent each month is $800. After one person’s rent is increased by 20 percent the new average rent is $850. What was the original rent of the friend whose monthly rent increased?
A.$800
B.$900
C.$1,000
D.$1,100
E.$1,200
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Re: The average (arithmetic mean) amount of money that a group of four fri  [#permalink]

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New post 22 Aug 2018, 20:08
Average rent for 4 people = 800.
Total rent becomes = 800*4 = 3200.
One person rent has increased by 20%, Then the averagr rent becomes 850. Total becomes 850*4 = 3400.
Differnece between Old and new rent = 3400-3200 = 200 Increase.
New rent becomes 200/.2 = 1000.

I think the question should be changed be the new rent not original.

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Re: The average (arithmetic mean) amount of money that a group of four fri  [#permalink]

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New post 22 Aug 2018, 22:23
Afc0892 wrote:
Average rent for 4 people = 800.
Total rent becomes = 800*4 = 3200.
One person rent has increased by 20%, Then the averagr rent becomes 850. Total becomes 850*4 = 3400.
Differnece between Old and new rent = 3400-3200 = 200 Increase.
New rent becomes 200/.2 = 1000.

I think the question should be changed be the new rent not original.

Posted from my mobile device


Hi Afc0892,

If old rent of any one of the 4 persons is x, after an increase of 20% of rent for that person, new rent=1.2x

To find: x(original rent)=?

Difference between Old and new rent = 3400-3200 = 200 Increase.
Or, Sum of new rent-Sum of old rent=200
Or, (1.2x+sum of rent of other 3 persons)-(x+sum of rent of other 3 persons)=200
Or, 0.2x=200
Or, \(x=\frac{200}{1.2}=$1000\)
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Re: The average (arithmetic mean) amount of money that a group of four fri   [#permalink] 22 Aug 2018, 22:23
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