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11 Mar 2020, 04:15
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D
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The average (arithmetic mean) of 11 numbers is 10. When one number is eliminated, the average of the remaining numbers is 9.3. What is the eliminated number?
A. 14
B. 15
C. 16
D. 17
E. 18
A. 14
B. 15
C. 16
D. 17
E. 18
Updated on: 17 May 2021, 07:36
Originally posted by BrentGMATPrepNow on 11 Mar 2020, 06:18.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:36, edited 1 time in total.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:36, edited 1 time in total.
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Bunuel
The average (arithmetic mean) of 11 numbers is 10. When one number is eliminated, the average of the remaining numbers is 9.3. What is the eliminated number?
A. 14
B. 15
C. 16
D. 17
E. 18
A. 14
B. 15
C. 16
D. 17
E. 18
The average (arithmetic mean) of 11 numbers is 10.
We can write: (sum of all 11 numbers)/11 = 10
Multiply both sides by 11 to get: sum of all 11 numbers = 110
When one number is eliminated, the average of the remaining numbers is 9.3
We can write: (sum of remaining 10 numbers)/10 = 9.3
Multiply both sides by 1 to get: sum of remaining 10 numbers = 93
What is the eliminated number?
We now know that:
sum of all 11 numbers = 110
sum of remaining 10 numbers = 93
110 - 93 = 17
Since the two sums differ by 17, the number that was eliminated must be 17
Answer: D
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11 Mar 2020, 10:04
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Bunuel
The average (arithmetic mean) of 11 numbers is 10. When one number is eliminated, the average of the remaining numbers is 9.3. What is the eliminated number?
A. 14
B. 15
C. 16
D. 17
E. 18
\(11*10 - x = 9.3*10\)A. 14
B. 15
C. 16
D. 17
E. 18
Or, \(110 - x = 93\)
Or, \(x = 110 - 93\)
So, \(x = 17\), Answer must be (D)
