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The average (arithmetic mean) of 4, 5, and x - 2 equals the average of

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The average (arithmetic mean) of 4, 5, and x - 2 equals the average of  [#permalink]

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New post 28 Dec 2017, 00:23
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A
B
C
D
E

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  15% (low)

Question Stats:

95% (00:45) correct 5% (02:19) wrong based on 31 sessions

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Re: The average (arithmetic mean) of 4, 5, and x - 2 equals the average of  [#permalink]

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New post 28 Dec 2017, 09:57
2
Answer C

Average of first three numbers = (4+5+x-2)/3 = x+7/3

Average of next three numbers = (x+3+?)/3

Both the averages are equal = x+7/3 = x+3+?/3

Answer : 4
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The average (arithmetic mean) of 4, 5, and x - 2 equals the average of  [#permalink]

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New post 28 Dec 2017, 14:08
1
Bunuel wrote:
The average (arithmetic mean) of 4, 5, and x - 2 equals the average of x, 3, and

A. 2
B. 3
C. 4
D. 5
E. 6

Eliminate the denominator and x

If \(\frac{4 + 5 + x - 2}{3} = \frac{3 + x + y}{3}\),
then on both sides, multiply by 3 and subtract x

\(\frac{4 + 5 + x - 2}{3} * (3) = \frac{3 + x}{3} * (3)\) -->

\(4 + 5 + x (- x) - 2 = x (-
x) + 3\) -->

\(7 = 3 + x\)
\(x = 4\)

Answer C
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The average (arithmetic mean) of 4, 5, and x - 2 equals the average of &nbs [#permalink] 28 Dec 2017, 14:08
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