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# The average (arithmetic mean) of 4, 5, and x - 2 equals the average of

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Math Expert
Joined: 02 Sep 2009
Posts: 43381
The average (arithmetic mean) of 4, 5, and x - 2 equals the average of [#permalink]

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27 Dec 2017, 23:23
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94% (00:27) correct 6% (02:19) wrong based on 16 sessions

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The average (arithmetic mean) of 4, 5, and x - 2 equals the average of x, 3, and

A. 2
B. 3
C. 4
D. 5
E. 6
[Reveal] Spoiler: OA

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Joined: 23 Feb 2017
Posts: 58
Re: The average (arithmetic mean) of 4, 5, and x - 2 equals the average of [#permalink]

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28 Dec 2017, 08:57
2
KUDOS

Average of first three numbers = (4+5+x-2)/3 = x+7/3

Average of next three numbers = (x+3+?)/3

Both the averages are equal = x+7/3 = x+3+?/3

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Joined: 22 May 2016
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The average (arithmetic mean) of 4, 5, and x - 2 equals the average of [#permalink]

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28 Dec 2017, 13:08
1
KUDOS
Bunuel wrote:
The average (arithmetic mean) of 4, 5, and x - 2 equals the average of x, 3, and

A. 2
B. 3
C. 4
D. 5
E. 6

Eliminate the denominator and x

If $$\frac{4 + 5 + x - 2}{3} = \frac{3 + x + y}{3}$$,
then on both sides, multiply by 3 and subtract x

$$\frac{4 + 5 + x - 2}{3} * (3) = \frac{3 + x}{3} * (3)$$ -->

$$4 + 5 + x (- x) - 2 = x (- x) + 3$$ -->

$$7 = 3 + x$$
$$x = 4$$

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The average (arithmetic mean) of 4, 5, and x - 2 equals the average of   [#permalink] 28 Dec 2017, 13:08
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# The average (arithmetic mean) of 4, 5, and x - 2 equals the average of

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