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The average (arithmetic mean) of the positive integers x, y, and z is
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30 Jul 2018, 21:59
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The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible value of z ? A. 5 B. 6 C. 7 D. 8 E. 9 NEW question from GMAT® Quantitative Review 2019 (PS00986)
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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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30 Jul 2018, 22:02
The smallest positive integer is 1 and 2nd smallest 2. So, 3*3 = 3+x. Hence, x= 6. B is the correct choice. Sent from my Redmi Note 3 using GMAT Club Forum mobile app



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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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30 Jul 2018, 22:06
Solution Given:• The average (arithmetic mean) of the positive integers x, y, and z is 3 • Also, x < y < z To find:• The greatest possible value of z Approach and Working: As the average is 3, • Then sum of all 3 = 3 * 3 = 9 Also, x < y < z and each are positive integers. To maximise z, we should take minimum value of x and y • Minimum possible x = 1 • Minimum possible y = 2 • Therefore, maximum possible z = 9 – (1 + 2) = 6 Hence, the correct answer is option B. Answer: B
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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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30 Jul 2018, 23:48
Bunuel wrote: The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible value of z ? A. 5 B. 6 C. 7 D. 8 E. 9 NEW question from GMAT® Quantitative Review 2019 (PS00986) Given \(\frac{x + y + z}{3} = 3\) x + y+ z =9 In order to maximize z we must minimize x and y. Note: x<y<z and all are positive integers. So the minimum value we have is 1. 1 + 2 + 6 = 9 The best answer is B.



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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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31 Jul 2018, 08:18
Bunuel wrote: The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible value of z ? A. 5 B. 6 C. 7 D. 8 E. 9 NEW question from GMAT® Quantitative Review 2019 (PS00986) \(x + y + z = 9\) We have to find the max value of z is minimizing the value of x & y Since, \(x < y < z\), minimizing x & y will be  x < y < z = 1 < 2 < 6 where x + y + z = 9, Thus Answer must be (B)
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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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17 Aug 2018, 22:04
Bunuel so zero isn't counted as an integer? This always confuses me.



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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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17 Aug 2018, 22:44
Shbm wrote: Bunuel so zero isn't counted as an integer? This always confuses me. 0 is an integer but it's neither positive nor negative. ZERO. 1. 0 is an integer.2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even. 3. 0 is neither positive nor negative integer (the only one of this kind). 4. 0 is divisible by EVERY integer except 0 itself. Check for more below threads: ALL YOU NEED FOR QUANT ! ! !Ultimate GMAT Quantitative MegathreadHope it helps.
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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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30 Nov 2019, 07:05
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Re: The average (arithmetic mean) of the positive integers x, y, and z is
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