Bunuel
The average marks of classes P, Q and R in a certain test is 62, 71, and 79 respectively. The average marks of classes P and Q is 66. The average marks of classes Q and R is 74. The average marks of classes P and R is approximately
A) 61.5
B) 64.5
C) 67.5
D) 73.5
E) 75.5
The answer depends on the strength of the classes, and let rose be p, q and r respectively.
LogicalIf short of time, I would use a bit of logic to get to the answer.
Average of P and Q is almost midway of the two averages, that is between 62 and 71.
So, p is slightly greater than q.
Average of R and Q is almost closer to 71.
So, q is greater than r.
The above two tell us that p>q>r: So, the average of P and R will be closer to p and between p and r.
Thus, A, D and E are eliminated.
Looking at the combined averages 66 and 74, 64.5 is too close to 62 as compared to distance from 79 to be correct.
C is correct option.
Weighted Average method 62–
4–66–
5–71, so p:q =
5:471–
3–74–
5–79, so q:r =
5:3Thus, 5:4 and 5:3 can be combined by multiplying p:q by 5 and q:r by 4 => p:q:r = 5*5:4*5:4*3 = 25:20:12
Or, p:r = 25:12
The combined average of P and R = \(62+\frac{12}{12+25}*(79-62)=62+\frac{12}{37}*17=62+\frac{1}{3}*17=62+5.66=67.6\)
C