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11 Apr 2018, 21:29
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
92% (01:25) correct
8%
(02:02)
wrong
based on 73
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The average of a set of 5 numbers is 20. If 4 additional numbers are added to the set, the average increases to 24. What is the average of the additional 4 numbers?
A. 22
B. 25
C. 26
D. 28
E. 29
A. 22
B. 25
C. 26
D. 28
E. 29
12 Apr 2018, 00:16
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Bunuel
sum of 5 no.=5x20=100
sum of 9 no.= 9x24=216
difference =216-100=116
116 is basically the total of 4 no.
average=116/4
=29
thus, the correct answer is E.
12 Apr 2018, 06:17
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Bunuel
\(A * n = S\)
The average of 5 numbers is 20
\((20 * 5) = 100 = Sum_1\)
4 numbers are added. Average increases to 24
\(n = (5 + 4) = 9\)
\((24 * 9) = 216 = Sum_2\)
\((Sum_2 - Sum_1) = Sum_3\) of the 4 extra numbers
\((216 - 100) = 116 = Sum_3\)
\(A = \frac{S}{n}\)
\(A = \frac{116}{4} = 29\)
Answer E
