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E
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The average of P numbers is x, and the average of N numbers is y. What is the average of the total numbers (P + N)?
A. (x + y)/2
B. x + y
C. (Py + Nx)/(xy(P + N))
D. (x + y)/(P + N)
E. (Px + Ny)/(P + N)
A. (x + y)/2
B. x + y
C. (Py + Nx)/(xy(P + N))
D. (x + y)/(P + N)
E. (Px + Ny)/(P + N)
27 Mar 2023, 05:52
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The average of P numbers is x
=> sum of P numbers is Px
and the average of N numbers is y
=> sum of N numbers is Ny.
Grand sum is Px + Ny
And the average of the total numbers (P + N) is
(Px+Ny)/(P+N)
Answer E
Posted from my mobile device
=> sum of P numbers is Px
and the average of N numbers is y
=> sum of N numbers is Ny.
Grand sum is Px + Ny
And the average of the total numbers (P + N) is
(Px+Ny)/(P+N)
Answer E
Posted from my mobile device
19 Apr 2023, 23:13
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Bunuel
Average = (Sum of numbers) / (Number of numbers)
Let's use this formula to find the average of P numbers, which is x:
x = (Sum of P numbers) / P
We can rearrange this formula to find the sum of P numbers:
Sum of P numbers = P * x
Similarly, let's use the formula to find the average of N numbers, which is y:
y = (Sum of N numbers) / N
We can rearrange this formula to find the sum of N numbers:
Sum of N numbers = N * y
Now, let's find the average of the total numbers (P + N). We know that the total number of numbers is P + N, and the sum of these numbers is the sum of the P numbers plus the sum of the N numbers:
Sum of P numbers + Sum of N numbers = P * x + N * y
The average of the total numbers is:
Average of (P + N) numbers = (Sum of P numbers + Sum of N numbers) / (P + N)
Substituting the expression we derived above for the sum of P numbers and the sum of N numbers, we get:
Average of (P + N) numbers = (P * x + N * y) / (P + N)
Therefore, the average of the total numbers (P + N) is:
(P * x + N * y) / (P + N)
Option E is correct.
