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30 Mar 2026, 19:00
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B
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Difficulty:
25%
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Question Stats:
83% (01:44) correct
17%
(02:47)
wrong
based on 65
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The average weight of a group of five students was 60 pounds. Three new students joined and the average weight of the group increased by five pounds. If no student weighs more than 90 pounds, what can be the minimum possible weight of the lightest of the three new students?
A. 30
B. 40
C. 50
D. 60
E. 70
A. 30
B. 40
C. 50
D. 60
E. 70
30 Mar 2026, 23:39
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Avg weight of 5 students = 60 ; Sum = 300
After 3 students joined avg weight of 8 students = 65 ; Sum= 520
Difference = 220 and constraint is no student weighs above 90. ie., max weight = 90
This 220 needs to be split into 3 parts such that we need to find the minimum possible weight of the lowest weight.
This can be done by maximizing the highest weights.
40,90,90 gives us a sum of 220 and we can see the lowest possible weight is 40.
Option B
After 3 students joined avg weight of 8 students = 65 ; Sum= 520
Difference = 220 and constraint is no student weighs above 90. ie., max weight = 90
This 220 needs to be split into 3 parts such that we need to find the minimum possible weight of the lowest weight.
This can be done by maximizing the highest weights.
40,90,90 gives us a sum of 220 and we can see the lowest possible weight is 40.
Option B
31 Mar 2026, 00:08
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x1 + x2 + x3 + x4 + x5 = 300
3 more students added.
x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 520
we need min weight of lightest of three person. to do that the other two needs to be at maximum. since no one can go beyond 90, the max weight those 2 can get is 90 each. and we know the sum of weight of first five students and that is 300.
300 + x6 + + 90 + 90 = 520
480 + x6 = 520
x6 = 40
Ans B
3 more students added.
x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 520
we need min weight of lightest of three person. to do that the other two needs to be at maximum. since no one can go beyond 90, the max weight those 2 can get is 90 each. and we know the sum of weight of first five students and that is 300.
300 + x6 + + 90 + 90 = 520
480 + x6 = 520
x6 = 40
Ans B
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