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Updated on: 10 Jun 2012, 22:12
Originally posted by alchemist009 on 10 Jun 2012, 17:43.
Last edited by Bunuel on 10 Jun 2012, 22:12, edited 2 times in total.
Last edited by Bunuel on 10 Jun 2012, 22:12, edited 2 times in total.
Edited the question.
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The base of a hemisphere is inscribed in one face of a cube and the entire hemisphere in contained within the volume of the cube. What is the ratio of the radius of the hemisphere to the length of a side of the cube?
A. \(\sqrt{2}:P\)
B. \(1:2\)
C. \(2:P\)
D. \(1:\sqrt{2}\)
E. \(2:1\)
here i found that logically D=S or 2r=S SO r/s= 1/2 ....is my reason correct?
A. \(\sqrt{2}:P\)
B. \(1:2\)
C. \(2:P\)
D. \(1:\sqrt{2}\)
E. \(2:1\)
here i found that logically D=S or 2r=S SO r/s= 1/2 ....is my reason correct?
10 Jun 2012, 19:56
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Also, the whole cube/hemisphere is a bit of a misnomer. The situation really is just a circle inscribed in a square. Once you draw that, it's easy to get B
