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The combined cost of Car X and Car Y is 7250$

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The combined cost of Car X and Car Y is 7250$  [#permalink]

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New post Updated on: 10 Mar 2018, 12:40
3
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A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

56% (00:57) correct 44% (00:36) wrong based on 9 sessions

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The combined cost of Car X and Car Y is 7250$. Had the Car X been 25% cheaper, and the Car Y been 20% costlier, Combined cost would have been 6,450$. How much Car X is costlier than Car Y?

A : 500
B : 800
C : 1000
D : 2750
E : 2250

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Originally posted by prady2231 on 10 Mar 2018, 02:25.
Last edited by prady2231 on 10 Mar 2018, 12:40, edited 2 times in total.
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Re: The combined cost of Car X and Car Y is 7250$  [#permalink]

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New post 10 Mar 2018, 04:55
Let say Car X is 4C1 as 25% = ¼ , Car Y is 5C2 as 20% = 1/5
Car X price decreased to 25%  New price will become 3C1
Car Y price increased to 20%  New price will become 6C2
Now we have 4C1 + 5C2 = 7250 & 3C1 + 6C2 = 6450 --- C1 – C2 = 800
Option D.
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Re: The combined cost of Car X and Car Y is 7250$  [#permalink]

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New post 10 Mar 2018, 09:21
prady2231 wrote:
The combined cost of Car X and Car Y is 7250$. Had the Car X been 25% cheaper, and the Car Y been 20% costlier, Combined cost would have been 6,450$. How much Car X is costlier than Car Y?

A : 500
B : 600
C : 700
D : 800
E : 1000


I am getting $2750 as answer.

if car X is 25% cheaper - it's price doesn't become 1/4th -- but rather 3/4th of original price.

first equation : \(X+Y = 7250\)
second equation : \(0.75X + 1.20 Y = 6450\).

Solving both for X, Y we have : Y = 6750/3

using first equation and solution of Y to find X - Y ( ANswe r to prompt question of " how much is X costlier than Y)

We get \(X - Y = 2750\)

Please let me know what you guy's think.

Hope this helped....
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The combined cost of Car X and Car Y is 7250$  [#permalink]

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New post 10 Mar 2018, 12:03
[quote="prady2231"]The combined cost of Car X and Car Y is 7250$. Had the Car X been 25% cheaper, and the Car Y been 20% costlier, Combined cost would have been 6,450$. How much Car X is costlier than Car Y?

A : 500
B : 600
C : 700
D : 800
E : 1000[/quote]
[url=https://gmatclub.com:443/forum/memberlist.php?mode=viewprofile&un=Gladiator59][b]Gladiator59[/b][/url] , I got $2,750 as well. [EDIT]

X + Y = 7250
Y = 7250 - X

.75X + 1.2Y = 6450
.75X + 1.2(7250 - X) = 6450
.75X + 8700 - 1.2X = 6450
-0.45X = -$2250
X = 5,000
Y = 7250 - 5,000 = 2250
X - Y = (5,000 - 2,250) = $2,750

Answer E

[url=https://gmatclub.com:443/forum/memberlist.php?mode=viewprofile&un=prady2231][b]prady2231[/b][/url] ,

Would you please check the question's wording and/or the answers?

EDITED: Corrected arithmetic at line (X - Y)
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Re: The combined cost of Car X and Car Y is 7250$  [#permalink]

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New post 10 Mar 2018, 12:46
1
Corrected the options. Correct answer is 2750.
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The combined cost of Car X and Car Y is 7250$  [#permalink]

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New post 10 Mar 2018, 13:10
prady2231 wrote:
The combined cost of Car X and Car Y is 7250$. Had the Car X been 25% cheaper, and the Car Y been 20% costlier, Combined cost would have been 6,450$. How much Car X is costlier than Car Y?

A : 500
B : 800
C : 1000
D : 2750
E : 2250



\(x+y = 7250\) --> \(y = 7250 -x\)

\(x-0.25x + 1.2y = 6450\)

\(x-0.25x+1.2(7250 -x) = 6450\)

\(x-0.25x+8700-1.2x = 6450\)

\(x-0.25x-1.2x=6450-8700\)

\(-0.45x=-2250\)

\(x = 5000\)

\(7250-5000= 2250\)

so its E :)

looks like the OA was incorrect :)


Bunuel can you pay attention to this discussion :) shouldn't the correct answer be 2,250 ? :?

niks18 ?:)

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The combined cost of Car X and Car Y is 7250$ &nbs [#permalink] 10 Mar 2018, 13:10
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