prady2231 wrote:

The combined cost of Car X and Car Y is 7250$. Had the Car X been 25% cheaper, and the Car Y been 20% costlier, Combined cost would have been 6,450$. How much Car X is costlier than Car Y?

A : 500

B : 800

C : 1000

D : 2750

E : 2250

\(x+y = 7250\) --> \(y = 7250 -x\)

\(x-0.25x + 1.2y = 6450\)

\(x-0.25x+1.2(7250 -x) = 6450\)

\(x-0.25x+8700-1.2x = 6450\)

\(x-0.25x-1.2x=6450-8700\)

\(-0.45x=-2250\)

\(x = 5000\)

\(7250-5000= 2250\)

so its E

looks like the OA was incorrect

Bunuel can you pay attention to this discussion

shouldn't the correct answer be 2,250 ?

niks18 ?:)

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