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# The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q

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Math Expert
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The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q [#permalink]

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08 Feb 2018, 23:38
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The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q(9, 0), R(10, 3) and S(1, 3), respectively. The area of PQRS is

(A) $$9\sqrt{10}$$

(B) $$\frac{9}{2}*\sqrt{10}$$

(C) 27/2

(D) 27

(E) $$27\sqrt{10}$$
[Reveal] Spoiler: OA

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Re: The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q [#permalink]

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09 Feb 2018, 00:04
D.

Plotting the figure roughly on a graph we can conclude that PQRS is a parallelogram.

Hence area of parallelogram = b *d

Here b = 9 and d = 3

Hence area = 27
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Re: The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q [#permalink]

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09 Feb 2018, 01:02
Bunuel wrote:
The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q(9, 0), R(10, 3) and S(1, 3), respectively. The area of PQRS is

(A) $$9\sqrt{10}$$

(B) $$\frac{9}{2}*\sqrt{10}$$

(C) 27/2

(D) 27

(E) $$27\sqrt{10}$$

On plotting the points on the x-y coordinate, we see that it forms a parallelogram.
Area of parallelogram = Base x height = 9 x 3 =27
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Re: The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q [#permalink]

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09 Feb 2018, 23:24
Bunuel wrote:
The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q(9, 0), R(10, 3) and S(1, 3), respectively. The area of PQRS is

(A) $$9\sqrt{10}$$

(B) $$\frac{9}{2}*\sqrt{10}$$

(C) 27/2

(D) 27

(E) $$27\sqrt{10}$$

Answer is D as base is 9 and height is 3 if we plot on graph so area of quadrilateral is B*H= 9*3= 27. Oa plz
Re: The coordinates of the vertices of quadrilateral PQRS are P(0, 0), Q   [#permalink] 09 Feb 2018, 23:24
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