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23 May 2017, 07:26
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (02:16) correct
26%
(02:12)
wrong
based on 237
sessions
History
Date
Time
Result
Not Attempted Yet
Q.
\(\sqrt{z}/4 = a.bc\)
The decimal representation of the number is given above, where z is a positive number and a, b and c are single-digit non-negative integers. Is a = 0?
1. \(\frac{z^2}{4} > 64\)
2. \(\frac{z^{0.25}}{4}> 2\)
\(\sqrt{z}/4 = a.bc\)
The decimal representation of the number is given above, where z is a positive number and a, b and c are single-digit non-negative integers. Is a = 0?
1. \(\frac{z^2}{4} > 64\)
2. \(\frac{z^{0.25}}{4}> 2\)
Answer Choices
- A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.
Updated on: 31 May 2017, 05:11
Originally posted by EgmatQuantExpert on 23 May 2017, 07:26.
Last edited by EgmatQuantExpert on 31 May 2017, 05:11, edited 1 time in total.
Last edited by EgmatQuantExpert on 31 May 2017, 05:11, edited 1 time in total.
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The official solution has been posted. Looking forward to a healthy discussion..
23 May 2017, 10:32
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Statement 1: . (z^2)/4>64
Given that z is positive, lets take the square root of both the sides, we get
z/2 >8, which can written as z >16.
Taking square root of both sides again, we get
(z^1/2) > 4, dividing both sides by 4, we get, (z^1/2)/4 > 1. So a is not equal to 0. This statement is sufficient.
Statement 2: (z^1/4)/4 > 2
Squaring both sides we get, (z^1/2)/16 > 4, this can be written as
(z^1/2)/4 > 16
.
(z^1/2) > 64. So a is not equal to 0. This statement is sufficient.
Answer is D
Given that z is positive, lets take the square root of both the sides, we get
z/2 >8, which can written as z >16.
Taking square root of both sides again, we get
(z^1/2) > 4, dividing both sides by 4, we get, (z^1/2)/4 > 1. So a is not equal to 0. This statement is sufficient.
Statement 2: (z^1/4)/4 > 2
Squaring both sides we get, (z^1/2)/16 > 4, this can be written as
(z^1/2)/4 > 16
.
(z^1/2) > 64. So a is not equal to 0. This statement is sufficient.
Answer is D
