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Official Solution




Steps 1 & 2: Understand Question and Draw Inferences

Given:

    \(\sqrt{z}/4 = a.bc\)

    \(z > 0\)

    a, b, c = {0, 1, 2, 3 . . . 8, 9}

To find: Is a = 0?

    The answer is YES if \(\sqrt{z}/4\) < 1

    That is, if \(\sqrt{z}< 4\)

    Since \(\sqrt{z}\) is positive, the sign of inequality will remain the same upon squaring both sides

    So, the answer is YES if z < 16

    Else, the answer is NO


Step 3: Analyze Statement 1 independently

(1) \(\frac{z^2}{4} > 64\)

Multiplying the above inequality by 4 we get:

    \(z^2 > 64*4\)

Taking square roots we get

    z > 8 * 2 (Ignore negative roots as z is given as positive number)
    z > 16
    So, z is not less than 16

So, the answer is NO

Statement 1 is sufficient to answer the question



Step 4: Analyze Statement 2 independently

(2) ​\(\frac{z^{0.25}}{4}> 2\)


Since \(z^{0.25}\) is positive, squaring both sides twice will not change the sign of inequality:

    \(z^{0.25*4} > 8^4\)

    \(z > 2^{12}\)

So, z is not less than 16

Thus, the answer is NO


Statement 2 is sufficient to answer the question


Answer: Option D


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Q.

\(\sqrt{z}/4 = a.bc\)

The decimal representation of the number is given above, where z is a positive number and a, b and c are single-digit non-negative integers. Is a = 0?

1. \(\frac{z^2}{4} > 64\)

2. \(\frac{z^{0.25}}{4}> 2\)

From Statement 1, if z^2/4 > 64, then z^2 > (4)(64), and z > (2)(8), so z > 16. So √z/4 is thus greater than 1, and a cannot be zero, and Statement 1 is sufficient.

From Statement 2, z^(1/4) > 8, so z > 8^4. Then √z/4 is greater than √(8^4)/4 = 16, and the decimal representation of √z/4 cannot possibly look like "a.bc". So I have no idea how to now answer the question: is "a" the units digit in the decimal representation of √z/4? If so, then a can certainly equal zero. But if instead the question meant to say that a is the integer part of √z/4, then clearly a is greater than zero.

So it's impossible to answer the question, but the answer is A or D depending on what one guesses it means.
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