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The distance from Steve's house to work is 30 Km. On the way back Stev

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The distance from Steve's house to work is 30 Km. On the way back Stev [#permalink]

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New post 11 Jul 2016, 12:33
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The distance from Steve's house to work is 30 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work?

A. 5.
B. 10.
C. 14.
D. 15.
E. 20.
[Reveal] Spoiler: OA

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Re: The distance from Steve's house to work is 30 Km. On the way back Stev [#permalink]

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New post 11 Jul 2016, 14:08
D.
30 / s + 30 / 2s = 6
2s = 15

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Re: The distance from Steve's house to work is 30 Km. On the way back Stev [#permalink]

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New post 14 Jul 2016, 22:03
Time is in the ratio 2:1 :: to: fro office

Therefore, 2x+1x=6 hrs

Time take to come back - 2 hrs, distance travelled - 30km => Speed = 15kmph

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Re: The distance from Steve's house to work is 30 Km. On the way back Stev [#permalink]

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Re: The distance from Steve's house to work is 30 Km. On the way back Stev [#permalink]

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New post 14 Aug 2017, 00:32
30=s1 x t1 ; 30=2s1 x t2; So, s1 x t1 = 2s1 x t2 or t1 = 2t2 and t1 + t2 = 6

so we get s1 = 15/2 & s2 = 2 x 15/2 = 15.

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Re: The distance from Steve's house to work is 30 Km. On the way back Stev [#permalink]

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New post 18 Aug 2017, 09:09
Bunuel wrote:
The distance from Steve's house to work is 30 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work?

A. 5.
B. 10.
C. 14.
D. 15.
E. 20.


We can let the distance each direction = 30, the rate to work = r, and the rate from work = 2r.

Thus, the time going to work = 30/r and the time coming home from work = 30/2r = 15/r. Thus:

30/r + 15r = 6

45/r = 6

45 = 6r

7.5 = r

Thus, the speed on the way back from work is 2 x 7.5 = 15 mph.

Answer: D
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Re: The distance from Steve's house to work is 30 Km. On the way back Stev   [#permalink] 18 Aug 2017, 09:09
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