Hello, everyone. So far, the question is proving to be harder than I had anticipated for the community, but the sample size is small. The keywords that stand out to me here are
no solutions. For this to be true, we need to show that the two sides of the equation CANNOT be equal. How do we do that? Start by distributing that
a:
\(4x+3=ax+ab\)
Notice the mirroring on each side of the equation: 4
x would need to be equivalent to
ax, and 3 would need to be equivalent to
ab.
\(4x=ax\)
\(4=a\)
We know that
a must equal 4. Hence, we can strike answer (E). Now, applying the same logic as before, we can work on the remainder of the right-hand side:
\(3=ab\)
Since we know the value of
a, we can substitute:
\(3=(4)b\)
\(\frac{3}{4}=b\)
But now you have to be careful and remember the question. The problem tells us that the equation has
no solutions, not an infinite number of them, so it
must be true that although
a = 4,
b CANNOT be equal to 3/4. Hence, statements I and III must be true, and
the answer is (C).
If you were wondering why
b could equal 3, you could test that value independently of
a, and you could easily create a workable equation (for instance, when
a = 1).
I hope you had fun with this one. Good luck with your studies.
- Andrew