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The figure above represents a semicircular garden that is enclosed by

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The figure above represents a semicircular garden that is enclosed by  [#permalink]

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New post 09 Dec 2019, 03:11
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

59% (01:16) correct 41% (01:43) wrong based on 35 sessions

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The figure above represents a semicircular garden that is enclosed by 20 feet of fencing and a straight garden wall. What is the area, in square feet, of the garden?

A. \(\frac{20}{\pi}\)

B. \(\frac{50}{\pi}\)

C. \(\frac{100}{\pi}\)

D. \(\frac{200}{\pi}\)

E. \(\frac{400}{\pi}\)


Attachment:
1.jpg
1.jpg [ 23.49 KiB | Viewed 375 times ]

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Re: The figure above represents a semicircular garden that is enclosed by  [#permalink]

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New post 09 Dec 2019, 03:36
1
Bunuel wrote:
Image
The figure above represents a semicircular garden that is enclosed by 20 feet of fencing and a straight garden wall. What is the area, in square feet, of the garden?

A. \(\frac{20}{\pi}\)

B. \(\frac{50}{\pi}\)

C. \(\frac{100}{\pi}\)

D. \(\frac{200}{\pi}\)

E. \(\frac{400}{\pi}\)


Attachment:
1.jpg


Explanation:
2πr/2=20
r=20/π

Area of Semi-circle= (πr^2)/2= π{(20/π)^2}/2
= 200/π
IMO-D
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Re: The figure above represents a semicircular garden that is enclosed by  [#permalink]

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New post 09 Dec 2019, 22:43
Circumference = 2πr

Half of circumference is 20. So full circumference is 40.

Therefore:
2πr=40
=> πr=40/2
=> πr=20
=> r=20/π

Area of the garden
(πr^2)/2

= (π (20/π) (20/π))/2 = (400/π)/2 = 200/π Option D
GMAT Club Bot
Re: The figure above represents a semicircular garden that is enclosed by   [#permalink] 09 Dec 2019, 22:43
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