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# The figure above shows a cross section of a grand stand that seats

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Math Expert
Joined: 02 Sep 2009
Posts: 58464
The figure above shows a cross section of a grand stand that seats  [#permalink]

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08 Mar 2019, 03:23
00:00

Difficulty:

15% (low)

Question Stats:

80% (01:19) correct 20% (01:19) wrong based on 41 sessions

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The figure above shows a cross section of a grand stand that seats 1,000 people per 2 yards of slant height. What is the total number of seats in the grand stand?

A. 25,000
B. 35,000
C. 40,000
D. 50,000
E. 100,000

Attachment:

image049.jpg [ 4.37 KiB | Viewed 505 times ]

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Re: The figure above shows a cross section of a grand stand that seats  [#permalink]

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08 Mar 2019, 05:10
Bunuel wrote:

The figure above shows a cross section of a grand stand that seats 1,000 people per 2 yards of slant height. What is the total number of seats in the grand stand?

A. 25,000
B. 35,000
C. 40,000
D. 50,000
E. 100,000

Attachment:
image049.jpg

slant height = 60^2+80^2 = 10^2
or say 10
now 1000/2 = 500 people per yard
so 500*10 = 50000 seats
IMO D
Intern
Joined: 21 Aug 2018
Posts: 5
The figure above shows a cross section of a grand stand that seats  [#permalink]

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08 Mar 2019, 05:11
Since the figure isnt really clear (the dimension of the base) i am assuming the base to be 80 yards.

1000 people per 2 yards means 500/yard.

Now solving for slant height- remember 6,8,10 triplet. so slant height is 100.

Hence total number of seats=100*500= 50000.

Ans :D
Manager
Joined: 27 Mar 2016
Posts: 110
Re: The figure above shows a cross section of a grand stand that seats  [#permalink]

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08 Mar 2019, 07:25
Square root of (80^2+60^2) =100
total slant height = 100yds
1000 people in 2yds
50000 people in 100 yds
Ans. D
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Re: The figure above shows a cross section of a grand stand that seats  [#permalink]

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11 Mar 2019, 08:14
Bunuel wrote:

The figure above shows a cross section of a grand stand that seats 1,000 people per 2 yards of slant height. What is the total number of seats in the grand stand?

A. 25,000
B. 35,000
C. 40,000
D. 50,000
E. 100,000

Attachment:
image049.jpg

We have a 60-80-100 right triangle, so the slant height is 100.

Since the stadium seats 1,000 people per 2 yards of slant height, it seats 100 x 1000/2 = 50 x 1000 = 50,000 people.

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Re: The figure above shows a cross section of a grand stand that seats   [#permalink] 11 Mar 2019, 08:14
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